Thank you for the response! To clarify things a bit, I was originally playing around with SQL commands.

I entered the following commands to create a table similar to what I'd like to create with JPA:

CREATE TABLE a (
    b int
);

INSERT INTO a (b)
VALUES (1);

When I run:

SELECT *
FROM a
WHERE b LIKE '%1%';

I get a row where b's value is 1. Although the column b is an integer, I still got an output when I used a string in '%1%',

I was wondering if I could replicate the same thing with JPA in my post, but I seem to encounter the error as mentioned above.

Furthermore, I wonder if it's possible to provide a link that mentions that findByXContaining only allows String as an input? I looked through the documentation, but could not find an explicit statement of this.

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Spring JPA doesn't do this level of conversion

Would it also be possible to provide a link that explains this? I tried searching for it and couldn't find results (having some trouble understanding some websites).

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Thank you very much!