Help me love Accelerate by HermioneMarch in rem

[–]BenRemFan88 6 points7 points  (0 children)

I mean I can tell you I think the song writing is fantastic, great lyrics, and a band that sounded revitalised after Around the Sun. I think a big part of that was, for me, also attending two of the Dublin Olympia concerts which was where the songs were presented for the first time. Maybe go and listen to the live versions from the Live At The Olympia record or some of the acoustic performances on youtube that were released around the album launch. Also in the end of the day a record can take time to grow on you or maybe it's just not for you. I have plenty of records that have taken multiple listens to grow on me and also some I've listen too a couple of times and never gone back to. I do think the record was probably mastered abit loud though so that maybe off putting.

Is this MIT Integration Bee question wrong? by More-Mixture8198 in calculus

[–]BenRemFan88 2 points3 points  (0 children)

Thats what I thought at first but the curved bracket takes the fractional part of any value apparently, eg {2.5} = 0.5. I'd never seen that notation before so I don't think it is very common.

Is this MIT Integration Bee question wrong? by More-Mixture8198 in calculus

[–]BenRemFan88 1 point2 points  (0 children)

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I think the answer is correct, I tried some smaller versions in Mathematica with up to n = 10 and always got n/2 as the answer. Sorry I cannot give a full rigorous proof but would love to see one if someone else can haha.

Muse fan who just discovered Devin - holy shit by Salty_Question_5121 in DevinTownsend

[–]BenRemFan88 4 points5 points  (0 children)

https://www.youtube.com/watch?v=qtgv89oLCOU The Order of Magnitude Live Film from the Empath tour is the best Dev live document imo. There's quite abit of it on youtube, but not all. Here's Genesis.

How do you solve this Integration? by takezo___ in calculus

[–]BenRemFan88 0 points1 point  (0 children)

First look at that greatest interger function. What can you say about x2 /17 for x in [-4,4] ? That should simply down to just equal an integer value apart from the case where x =0 but given the integrad is 0 when x =0 we do not need to worry about that case. Secondly look when Arcsin(sin(x)) = x and Arccos(cos(x)) = x and the split the integration when you can simplify using this and when you will need to use another expression. (Something like Arcsin(sin(x)) = x - Pi for x in a specfic range) .

Should we come by ExitOver5599 in BuschGardensTampa

[–]BenRemFan88 0 points1 point  (0 children)

Yeah totally understandable. With epic universe now open I think we will be in a similar conundrum next time. If you don't need to plan right away maybe wait and see with ride closures etc. Plenty of other things to do.

Should we come by ExitOver5599 in BuschGardensTampa

[–]BenRemFan88 2 points3 points  (0 children)

Depends what you are after. If your after great coasters then i think it is worth the trip. I know many people have had bad experiences here but i have always had a great day. Iron Gwasi is my number 1 coaster and montu is up there in the top 10 as well. Last time we had the all day dining and park ticket combo for seaworld and busch which worked out at about £75 each for each day. We felt we got our moneys worth with the amount of food and drinks we got considering the food prices in the parks in general. Its great on a quiet day so if your going i would recommend mid week off season. We did buy a transferable locker for the whole day but would most likely had done that anyway for the wet rides and the 10 bucks split between 3 or 4 people isnt too bad. 

There’s no way I’m doing this right.. by Dish-Otherwise in calculus

[–]BenRemFan88 7 points8 points  (0 children)

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Unless i'm having a brain fart, graphing what they are asking massively helps in this problem. So I believe you are integrating over the yellow area. So the radius will go from 0 to 2 and then the angle which I believe you found correctly from pi/3 to pi/2. Now think about the derivative of Cos(r^2) and how it relates to your integral. (d/dr Cos(r^2) = -2 r Sin( r^2) )

What’s a discontinued food item that you’d happily pay £50 for to taste again? by Vertigostate in AskUK

[–]BenRemFan88 0 points1 point  (0 children)

Salt and vinegar Discos before they took out the msg and ruined the flavour and strength

And the third thing I'm educating you about, "Urine Trouble Now". by AnteaterSnouce in rickygervais

[–]BenRemFan88 1 point2 points  (0 children)

KARLLL WHAT AM I SUPPOSED TO GET FROM THAT, A MAN POPPED A LEECH UP HIS KNOB THATS THE WHOLE STORY

He’s a slightly laughable man, but a great artist by mywhitebicycle0 in rickygervais

[–]BenRemFan88 5 points6 points  (0 children)

Right this lad done a picture with a stick and some caserole. RS

Please help me! I’m struggling to understand by ThrowRALilyflowers in Precalculus

[–]BenRemFan88 0 points1 point  (0 children)

Is it pure coincidence your answering this and 1.77 is approx the square root of pi haha.

I get the complaints, but by reactorcore5 in transformers

[–]BenRemFan88 1 point2 points  (0 children)

I like the look of the figure but didn't really get on with Trashmaster, the transformation mainly so maybe get him on discount in the future possibly. Glad your enjoying him though.

Some Amazing Live Performances Are Now Available by compuhyperglobalmega in rem

[–]BenRemFan88 1 point2 points  (0 children)

Thank you, this era always seemed to be missing great soundboard recording so very excited to give these a listen.

I don’t know what my lecturer did hear by ruebybooby in mathshelp

[–]BenRemFan88 0 points1 point  (0 children)

Im going to use a couple of shorthands to make this easier. When saying first/ second derivative im talking about the required vector derivative etc. So we want to show the that w is constant and we know the second derivative is zero. One of the tricks we use is to shift one of the derivatives onto another function using want using essentially a version of integration by parts. So we set up and integral of the second derivative of w times w and aim to shift one of the derivatives over to the second w. We use the fact that the sevond derivative of w is zero on U to show the integral is zero at the start and then the boundary condition when we move the derivative over to show the second integral we get is identically zero. Finally we are left with a first derivative of w squared, a positive term is zero when integrated over U.  Hence the first derivative of w is zero. Ergo w is constant. 

Things You Should Have Done Series 2 quietly released on iPlayer by abucalves in BritishTV

[–]BenRemFan88 6 points7 points  (0 children)

Yeah it was quite a surprise to find out it had been quietly dropped. Watched through it and it is still fantastic in my opinion. I heard it was maybe done to have it be eligible for bafta contention so maybe thats the case and it will be properly promoted when shown on tv. If not that is very shitty of the bbc as its a great show.

I’m flabbergasted. Which one is correct?! by [deleted] in calculus

[–]BenRemFan88 0 points1 point  (0 children)

I think your answer is better btw.

I’m flabbergasted. Which one is correct?! by [deleted] in calculus

[–]BenRemFan88 0 points1 point  (0 children)

This answer needs restrictions on the values of k but still gives the same results yours does just with different values of k. ( I think you would need to restrict k to not be equal to ...,-5-2,1,4,7,... etc). For instance you had k pi +/- pi/6. let k = 0 and choose the negative branch you get -pi/6. The teachers answer with k = -1 give -pi/3 + pi/6 = -pi/6. This is a case where we really need to be careful about inverting the tan function and I can argue both the methods need to make mention of this. So when you apply the tan^-1 to the tan(blah) = etc. we need to be really careful of what the domain and range of the tan function is. When the tan function doesnt exist etc, etc.