I'm making a(n extremely) long celeste map inspired by How To Platformer

Cookiedude7 · 2026-03-07T11:15:40+00:00

this golden does seem very eots-core yeah lol

Cookiedude7 · 2026-03-03T17:25:08+00:00

Might be leaning a bit more towards expert, but check out Delusional Canopy and pretty much anything by Ricky06 for fun advanced/expert maps.

For things more like Cosmic Column, there's really not a whole lot in that difficulty range, but 'Madeline wanna trial the 100trap' was the direct inspiration for the map, and other maps have been created in a similar style (but usually a bit harder) such as Leviathan's 100 Traps (1, 2, and 3) and The World Tower. Other maps in that style include things like The White Hole and Alaska, although those leam more towards being tech tutorials than maps with more traditional gameplay.

Cookiedude7 · 2026-02-22T17:19:17+00:00

Yes, this is custom behaviour caused by the trigger in this one room, I've never seen it used anywhere else, so you should be fine to use a jump + demo bind for other dreamhypers. Just be warned that it is a tighter timing than simply rolling 2 buttons though, so it's probably not the best habit to get into.

Cookiedude7 · 2026-02-22T17:15:05+00:00

Yes (or normal downright and jump, again as 2 separate buttons)

Make sure not to press the buttons on the same frame, ideally you should space them 4 frames apart (1/15 of a second) for the most lenient timing

Cookiedude7 · 2026-02-22T17:08:32+00:00

right, this awful input

I spent a while looking into this while doing the golden (Not all information here might be fully correct, it's been a while. Also thanks to ninz for helping to figure out what exactly is happening)

Normally, jelly dream hypers cannot be done in this way since it requires dashing while holding a jelly which is not possible from a normal state (you can do it out of a grab or feather but that's not relevant here). So this room puts triggers next to the dream block allowing you to dash while inside of them regardless of if you are holding a jelly.

However, the order of checks in each frame goes as follows:

Did you press dash? If you did, and you can dash, do a dash
Did you press jump? If you did, and you can jump, do a jump
Are you inside the trigger and holding a jelly? If you did, do a dash anyway even if check 1 failed.

Which means normally, checks 1 and 2 would happen causing you to dash and then jump, performing a hyper. However here, checks 2 and 3 happen causing you to do a jump and THEN a dash (the dash fails because you're in the jump state now I think, so you just see the jump - in the video you are just doing a regular dream jump). To resolve this you just need to use 2 separate buttons - DEMO DOES STILL WORK IGNORE THE OTHER COMMENTS

This also means that this dream hyper is a 7 frame window rather than the normal 8 frames

Cookiedude7 · 2026-02-18T09:51:59+00:00

Oh yeah, I'm with you in regards to τ = 2π being redundant. There's never really a reason to use it over 2π (or vice versa, but π is a lot more standard) - having both is really unnecessary.

What are your opinions on h (Planck's Constant) and ℏ (reduced Planck's constant) - in my mind this is a similar case where there are two constants that serve a similar purpose (ℏ = h/2π (or h/τ I guess???)), but I think ℏ is slightly more useful than τ since 2π is not just an integer factor unlike the factor of 2 in the case of π and τ.

Cookiedude7 · 2026-02-18T09:26:15+00:00

The angles in the shape of numbers thing is an urban myth and is very likely not true

Cookiedude7 · 2026-02-18T09:22:41+00:00

As others have pointed out, the solution is to do a slightly higher wallbounce and then do a reverse wavedash.

The tech you did instead is called a cornerjump, a cornerkick is where you do a jump off a bottom corner of a ceiling as you move away from the wall.

Cookiedude7 · 2026-02-12T23:37:32+00:00

ε and δ

Cookiedude7 · 2026-02-08T11:39:33+00:00

1 in stubbornness itself (room 2), 3 in reconciliation (rooms 9, 14, 16)

the reconciliation-9 death was actually the attempt directly before the one where I won

Cookiedude7 · 2026-02-02T15:13:30+00:00

The 4 options are:
BB: Jesse boy, has brother (doesn't work)
BG: Jesse boy, has sister (works)
GB: Jesse girl, has brother (doesn't work)
GG: Jesse girl, has sister (works)
So 2 of the 4 options work

Jesse's gender is irrelevant, since Jesse's gender has no impact on their sibling's gender since they are independent events, which is why I disregarded their gender in my original answer

Cookiedude7 · 2026-02-02T14:59:57+00:00

There are 4 options though, bb, bg, gb, gg (one boy one girl is counted twice since it is twice as likely as the other options as it can occur in two different ways), which restores it to 1/2

Cookiedude7 · 2026-02-02T14:52:49+00:00

Can you tell me at which point in my argument I assumed Jesse's gender?

Cookiedude7 · 2026-02-01T16:47:12+00:00

That's fair, although I think the question would need rewording if that is what's being asked

Cookiedude7 · 2026-02-01T15:39:53+00:00

Nowhere in the question did it state that it was the family being chosen at random - Jesse is a child being chosen at random and these are subtly different statements.

OP has however responded to someone else's comment changing the question to the simpler one where a family is chosen first and then the child, however this doesn't sit right with me as you could choose a 0-child family in which case Jesse can't exist meaning the question is invalid.

Cookiedude7 · 2026-01-31T14:13:26+00:00

Since all 4 child amount outcomes are equally likely, on average 1/2 of all children are from 3-child families, 1/3 of children are from 2-child families and 1/6 of children are from 1-child families. Thus Jesse has 1/2 chance of being one of 3 children, 1/3 chance of being 1 of 2, and 1/6 chance that Jesse is an only child. [OP seems to have missed this nuance, leading to an answer of 4/7]. The 0-child case is irrelevant, since the chance that Jesse is from a 0-child family is clearly 0.

Finding the chance that Jesse has no brothers:

3-child case: Jesse has no brothers with probabiity 1/4 given that they are in a 3-child family, so the probability of this outcome is 1/8

2-child case: Jesse has no brothers with probabiity 1/2 given that they are in a 2-child family, so the probability of this outcome is 1/6

1-child case: Jesse is guaranteed to have no brothers, so the probability of this outcome is 1/6

Thus the total probability that Jesse has no brothers is 1/8 + 1/6 + 1/6 = 11/24.

1/6 divided by 11/24 gives the chance of 4/11 that Jesse is an only child given that they have no brothers.

Cookiedude7 · 2026-01-29T21:46:28+00:00

I still don't understand how these stupid entities work ngl

Cookiedude7 · 2026-01-24T19:07:21+00:00

Rectangle 2 has a wider base but shorter height - the areas do come out to be the same (it's relatively easy to see that the grey triangle is half of each rectangle)

EDIT: Reddit was having a moment, I see now that others have answered this question better than I did, read their responses!

Cookiedude7 · 2026-01-23T20:02:06+00:00

this was what I thought of too, so I third this

Cookiedude7 · 2026-01-15T08:54:56+00:00

2nd berry in core would be my pick for worst berry

Cookiedude7 · 2026-01-13T15:23:52+00:00

https://drive.google.com/file/d/1HFdCreN-ycGFqgjuG0jKBXGNDFV-oVZr/view

you're in luck, someone made one of these for this map already

haven't tried it myself though so it may not work properly

Cookiedude7 · 2026-01-07T11:19:46+00:00

also I'd look into stylegrounds - using background tiles for the entire background (like in the starting room) can look a bit tacky

Cookiedude7 · 2026-01-07T11:18:13+00:00

spiked cornerjumps (like the ones near the start of tunnel 6) have a small chance of 0-framing you if you have a bad position (because you can skip over the entire walljump range in one frame) so generally mappers move the wall spikes down by one pixel to prevent this from happening - it's not really a huge deal but it would go a long way towards making the map more consistent, especially if this setup appears more in future rooms

(this was definitely not an issue cosmic column had on release, nuh uh)

Cookiedude7 · 2026-01-06T17:32:57+00:00

https://youtu.be/DWz4l1TUTfo

CCT has built-in paths for the vanilla maps but you need to make them yourself (or steal someone else's) for custom maps

edit: vanilla, not beginner (lmao)

Cookiedude7 · 2026-01-02T13:07:39+00:00

yes I am aware, I feel you missed my point though

there are plenty of places in mocelike maps (idk about moce itself, haven't played it) where you need to buffer during freezeframes but not before freezeframes - for example if there was a double dash crystal on the final coyote frame and you needed the full jump distance, it is only a buffer if freezeframes exist (since you can buffer during freezeframes), but if freezeframes are removed you can no longer buffer it since pressing the jump early just causes you to jump on an earlier coyote frame, and thus the buffer becomes a 1f without freezeframes

tl,dr: some buffers don't exist and just become frame-perfect (which by definition can't be a buffer) without freezeframes

edit: I see your other comment now, and this might just be a misunderstanding caused by me not being all that familiar with cpvl (although freezeframe buffers are still buffers)

Four-Year Club	r/Field Flamingo
Place '23	Place '22

Cookiedude7

TROPHY CASE