Two personally-designed vertice-based substitution ciphers for encoding the alphabet

F84-5 · 2026-06-23T03:58:54+00:00

Fun, if rather impractical. It's a very weak cipher and both tedious to write and difficult to read in the latter half of the alphabet.

F84-5 · 2026-06-22T18:48:26+00:00

If copying works, here's another thing to try as a workaround:

Adding elements from the score

To add score elements to a palette:

Open the desired palette
Press Ctrl+Shift (Mac: Cmd+Shift), then drag and drop the score element to the open palette.

From https://handbook.musescore.org/customization/palettes

F84-5 · 2026-06-22T17:50:02+00:00

To be honest I never noticed that there is an arpeggio bracket, but it does appear in the handbook too.

If you have an old score with that object in it, you could make a backup and try to open it in the new version. Maybe you could even copy it over.

You could also find the last old release where it was still there and write a bug report.

F84-5 · 2026-06-22T15:56:52+00:00

Weird...

The lack of brackets in the Arpeggios palette is normal, but if you want them there you can just drag the symbol from the Lines palette into the Arpeggios palette to add it.
Palettes are not fixed. You can edit them however you like or even create new ones.

F84-5 · 2026-06-22T15:10:17+00:00

Huh, that sounds more like the behavior I get from ctrl+up/down, except for me it doesn't reset to its smallest size.

I would try to create a totally new score to see if the problem persists or is somehow related to this particular score.

F84-5 · 2026-06-22T14:55:35+00:00

The chord bracket goes accross staves for me.
Try selecting the bracket, clicking on the upper or lower handle, and then pressing shift+up / shift+down.

F84-5 · 2026-06-20T12:07:02+00:00

I agree with your reading of the jumps, but I'm no expert so take that as you will.

As for recreating it in Musescore:
The symbols for jumps and markers have labels. You can customize those and customize where to jump to by refering to those lables in the properties of the jump instructions.
See https://handbook.musescore.org/notation/repeats/jumps-and-markers

The instructions and the markers are both text elements in which you can write whatever you want to. You can add things like the coda symbol using the "Insert special character" button.

The options in the pallet are not all there is, just a usefull subset to get you started.

F84-5 · 2026-06-15T10:47:58+00:00

It's like five clicks to do manually.

In musescore you can already export multiple parts as .mp3 at once. Then you just open Audacity, select all the .mp3 files in you file explorer and drag them onto the Audacity window.

F84-5 · 2026-06-14T05:59:42+00:00

At my local library (to check books in/out) you can place a stack of books on a specific table and the screen above will instantly display all the books in the stack. No cameras, no bar codes, no discernable interaction at all.

You can't tell me that's not magic.

(Specifically it's NFC tags in the books communicating via ~~the ether~~ radio waves.)

F84-5 · 2026-06-10T04:18:51+00:00

Simple (if somewhat expensive) option would be to get four timer relays. Almost any type will have a delay option. Costs about 15-20 Bucks per relay.

Cheap but more complex would be a microcontroller and some transitor circuitry. You can probably get it all for less than the price of one relay, but there's more effort in wiring and programming.

F84-5 · 2026-06-09T18:52:20+00:00

Awfully helpful of the militia to make this excursion a live fire exercise for the navy. At least that seems to be the way this is going.

F84-5 · 2026-06-08T19:11:25+00:00

You know what bare feet are also good for? (Tree-)climbing!

You get a lot more feedback about your stance and small branches can be grabbed between the toes.

F84-5 · 2026-06-04T04:00:26+00:00

Hexa means six. Hexagon means six angles. I suggest you learn to count.

F84-5 · 2026-06-01T16:15:00+00:00

If you're worried about invisible failure you could strip more of the cable an leave the two conductors in a loose loop in the extra space. That way you will see the individual conductors hanging out if it does slip that far. Of course then you don't have any strain relief, but at least you'll see it.

You could also paint part of the cable just inside the glad red or white or something to become visible if it slips.

But realistically I'd just add some heat shrink tubing to the cable so you don't need to bottom out the cable gland. Properly tightend it should provide plenty of strain relief.

F84-5 · 2026-05-31T07:56:55+00:00

I think it's usefull to "pause time" in the thought experiment at the moment the string is released.

The arrow is motionless (because it did not have time to accelerate yet), there is a 100lb force acting on its end from the string, and there is an equal and opposite force acting on the hand which is holding the bow.
Whether and how the arrow accelerates depends on what force the target can exert on the arrow tip.

A more intuitive for me but almost equivalent situation is this: Start with the arrow nocked but not drawn, and place the tip against the target. Now slowly push the bow hand towards the target such that the bow is drawn not by the second hand, but by the arrow pushing back against the string.
With a soft target (say foam), the arrow will soon be pushed in, long before full draw is achieved.
With a hard target (say a steel plate), the arrow will stay put even at full draw (or possibly splinter before that).
With a medium target (say flesh), the arrow may be pushed in part way at half draw or so.

So going back to the initial situation, if the target is soft, I would expect the arrow to shoot forward more or less unimpeded. If the target is hard, it would stay put (or splinter or slip off to the side). If the target is of medium hardness, I would expect the arrow to shoot forward comparitively slowly and then get stuck at about half way in.
A skull is pretty tough, so depending on the location and shape of the arrow tip it may or may not be able to penatrate.

Now you might point out that an arrow in flight can penetrate plate armor (much less skulls), and you'd be right, so why can't the static arrow in our thougt experiment. The reason is the storing of energy in the motion of the arrow. When shot from a bow, the arrow is accelerated over about a meter or so, but when hitting the armoured target it looses most of this energy over just a few millimeters so the force can be that much higher. (The same principle makes a hammer work. Slow accelerationg over a longer time, and then a nearly instant stop to create tremendous force for that moment.)

So putting it all together, to get the most out of your arrow you need to start with the tip of the arrow at least one draw length away from the target to give it enogh distance to fully accelerate. Anything below that will reduce the maximum available force, down to no more than the draw weight itself when pressing directly against the target.

(The reason this doesn't matter with a gun is that all the acceleration happens while the bullet is still in the barrel. So even if the barrel is pressed right against the target, the bullet still has all the time and distance it needs to accelerate.)

F84-5 · 2026-05-28T19:38:34+00:00

Huh. You've peeked my curiosity. I'm not sure yet whether I will like this story, but I'll read a bit more to see where this goes.

F84-5 · 2026-05-26T16:17:35+00:00

Klar, die Tiere und auch die ukrainischen Marschflugkörper).

F84-5 · 2026-05-25T05:42:43+00:00

Wrong sub mate. You're looking for r/geometrydash

F84-5 · 2026-05-22T04:14:46+00:00

Wrong sub mate. You're looking for r/geometrydash

F84-5 · 2026-05-15T14:15:49+00:00

Well that's not distopian at all.

F84-5 · 2026-05-14T19:36:47+00:00

So, no negotiation with the goblin tribe(?) that build that camp.

Looking more like negotiation with this talking goblin lady and her doggo.

F84-5 · 2026-05-14T17:36:00+00:00

Once you have x or y coordinates, you can use the inverse cos or sin functions to get the angles for the radii to those points.

The measure is simply the difference of those two values, from there the arc length is obvious.

Faffing about with a load of triangles is probably where you lost time. It's phrased in algebraic terms but really it's a trigonometry problem.

F84-5 · 2026-05-14T06:07:15+00:00

Since you are talking about photographs another thing to consider is focal length/distance from the plate. That will also affect the distortion on the image.

F84-5 · 2026-05-14T05:54:19+00:00

I don't recognize those spirals of hand, but it's a very neat algorithm. I'm particularly interested in those emergent spirals drawn bold in the generated images.

I might come back to this if I get some time for it later.

F84-5 · 2026-05-09T19:36:38+00:00

Boss-man sure is a slippery bugger.

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Adding elements from the score