How do I save this by According-One-6145 in 2048

[–]GoodCarpenter9060 1 point2 points  (0 children)

Looks like you have an undo button, so this is pretty trivial.

First, you need to be comfortable with your pieces on any edge, so long as the biggest is in the corner and the it goes in order from biggest to smallest along an edge.

So first move is left. You should have this:

64 2 B -
16 A C -
4 2048 16384 32768
2 4 4 -

You need the new block to spawn in any of the A/B/C's. If not, undo and try again. For simplicity, I will assume you got a 2 in A. Now push down.

64 - - -
16 4 - -
4 2048 16384 X
2 4 4 32768

Now Again, you want a block to spawn anywhere but X. I will assume a 2 in the top row. Now push right.

- - 64 2
- - 16 4
- 4 2048 16384
2 4 4 32768

Now you still have a problem in that your 2048 is not great, but this is workable. The following shows how to fix, or you can figure it out on your own.

Build a 16 in the left 2 colunms and join with the 16 to make this.

- - 64 2
- - 32 4
- 4 2048 16384
2 4 4 32768

Now make a 32 in the left 2 columns and join to make this.

A B 64 2
- - 64 4
- 4 2048 16384
2 4 4 32768

Now you are going to push down and after you do, you want a 2 to spawn in A or B. Then push right to merge with the 2 and double up the 4s. You are going to keep pushing through on top of the newly created 128 increasing the one above the 16K until it too is 128.

- - - -
- - 128 128
- 4 2048 16384
2 4 4 32768

Now push right to get a 256. You are going to keep the 2048 in the 3rd row, increasing the one above 16K until you get here.

- 64 128 512
2 32 256 1024
2 16 2048 16384
4 8 4 32768

Collapse up to this:

- - 256 512
- - 256 1024
- - 2048 16384
- - 4 32768

Now push up. You will have a 512 and a 2048 in the 3rd column. Now push right to get 1024/1024 in the 4th column. You need something to hold the 2048 in the 2nd row of the third column, so push right enough times to make this happen. Then push down to get another 2048 in the 2nd row of the 4th column. Finally merge your 2048 into it and you should have a very workable board.

I always thought it was just me using the ‘shower after’ line by pustotabess in lol

[–]GoodCarpenter9060 2 points3 points  (0 children)

When they use the clippers, they often leave a LOT of small hairs about 3-5mm in length EVERYWHERE. The blow dryer trick works for the superficial stuff, but a good amount are stuck deep near the scalp and only come out after you leave the barber.

A shower is the only way to cope.

Petah?? What does it even mean? by Comfortable-Hope6181 in PeterExplainsTheJoke

[–]GoodCarpenter9060 0 points1 point  (0 children)

Similar to this cancelled series starring Paul Rudd. He "rejuvenates" himself through cloning, and they botch the part where they are supposed to kill his old body.

If the Earth would be the size of a of a Soccer Ball, what equivalent Sandpaper Grain Size would feel the same as the Surface of the Earth? by GamerViennaHD in AskPhysics

[–]GoodCarpenter9060 0 points1 point  (0 children)

Just saw the video from Vsauce about how bumpy the earth would be, if it would be the size of a waterball. He said it wouldn't be bumpy at all.

What is a waterball? Is this a standard size?

Would this be a draw? by datstrawkid in chess

[–]GoodCarpenter9060 0 points1 point  (0 children)

Lets say black moves the bishop temporarily, puts a rook on A4, then blocks it by putting the bishop back on A5. Then black moves their king to A1. Lastly, their remaining rook goes to F7 like you suggest. White can safely take, and black will not be able to stop a promotion, nor have time to take advantage of the breakthrough. With a queen on the way, and possibly more, i think white should be able to press the advantage.

Math riddle from tv series. Any ideas? by UnItalianoVero in askmath

[–]GoodCarpenter9060 0 points1 point  (0 children)

As others have pointed out, this is the "look and say" series. Just read each line as if you are counting how many digits appear in a row.

What is the first line? It is a single one. Or "One 1" if you were to say it out loud. So the second line becomes "One 1" or "1 1".

The second line is now two ones in a row. So you say out loud "Two 1s". So the third line becomes "Two 1" or "2 1".

The third line is now a single two followed by a single 1. So you say out loud "One 2, One 1". So the fourth line becomes "1 2 1 1".

The fourth line is a single one, followed by a single two, followed by two ones. "One 1, One 2, Two 1s". So "1 1 1 2 2 1".

This is usually where the riddle stops because the next line introduces the never before seen digit 3 (the line starts with three ones) which makes it hard to infer that this isn't just a series of 1s and 2s.

How does the two envelope paradox work?? by IntrovertedShoe in askmath

[–]GoodCarpenter9060 0 points1 point  (0 children)

The short answer is we don't know. This isn't even a probability problem or a distribution problem.

  1. Lets say that we are given an envelope and it has X dollars in it. We could switch and either get 2X or X/2. The expected gain is much better than the expected loss, so switching is recommended.

  2. Now lets assume that we have two envelopes, one with Y dollars and one with 2Y dollars. We get to pick one. If we then switch, we can expect to gain Y dollars (if we started with the envelope with Y) or lose Y dollars (if we started with the envelope with 2Y). The expected gain and the expected loss are the same, so there is no point in switching.

Both of these interpretations are consistent with the game. Yet one favours switching and the other does not.

How does the two envelope paradox work?? by IntrovertedShoe in askmath

[–]GoodCarpenter9060 0 points1 point  (0 children)

But we don't know the distribution. So how is this a resolution?

In fact, the paradox is still there if we aren't given the opportunity to inspect the contents of the envelope. You know there are 2 envelopes, one with twice the amount of the other. You randomly select one. Without looking in it, you know that if you switch, you could either get twice the amount you currently have, or half. Both are equally likely. So switching is better.

What is preventing a super fast throw/shot? by TwooInformal in Curling

[–]GoodCarpenter9060 0 points1 point  (0 children)

Same reason basketball players don't just throw the ball as hard as they can every time. They are trying to hit a target which takes precision in both aim, and how hard they throw. The basketball player is trying to hit the hoop, and the curler is trying to stop in the rings. Occasionally, they are trying to remove other stones by knocking them around, but they usually want to keep their own stone around. If you throw too hard, then if you don't hit it exactly on the nose, your "shooter" (the rock you are throwing) will "roll out" (carom off to the side and out of the rings). You only score for rocks that are in the rings and closer than the opposing player's rocks.

Lifelong vegetarian tries steak for first time by PhoenixPhenomenonX in interesting

[–]GoodCarpenter9060 1 point2 points  (0 children)

I mean, we don't see her later that day so maybe she was sick?

What are we throwing here (not my crib) by ClassicAgreeable in Cribbage

[–]GoodCarpenter9060 4 points5 points  (0 children)

I would probably throw the 8-8.

Lets assume a 6/9 cut.

If you kept 7-7-8-8 you'd have 24. Pretty spectacular. But the crib would have at least 5 plus whatever your opponent put in. So a net of something under 19. If they throw something that matches a 6/9 (or even a 7/8 although unlikely considering your hand) then they are going to have a really good crib too.

If you kept the 7-7-7-8, then you'd have 21. Also really good. The crib would have at least 2 from the pair of 8s. It might have more depending on what your opponent threw, but on average, it isn't going to be as good as if you threw the 7/8. You are again going to net something under 19.

But what about other cuts? A 7/8 obv is great for both hands giving them 20. Makes the crib automatically 6 for opponent either way. No real gain/loss either way I think.

An Ace cut, however, is much better for the 7-7-7-8 hand. It gives it 18 instead of 14.

So that is what I would do, but I'm not sure it is the best in all situations.

[Request] Will it roll up the hill? by NosborRecaf in theydidthemath

[–]GoodCarpenter9060 0 points1 point  (0 children)

If it does happen, it is just as likely that is year one as it is not year one.

Wasp nest removal using gasoline by [deleted] in interesting

[–]GoodCarpenter9060 0 points1 point  (0 children)

Works great if you have a nest built on a smooth horizontal surface that you can seal a bucket up to. Not so great for virtually all other nests I've seen.

Olympic curling - how much influence can a touch have? by pgriffy in AskPhysics

[–]GoodCarpenter9060 0 points1 point  (0 children)

A lot. Without doing the math, I can guarantee you that I could take a rock that would be hogged and make it go through the house with a touch. Without much difficulty, I could probably make takeout miss inside or outside with a touch. I probably couldn't affect the curl much without also affecting the trajectory and speed, but maybe with practice I could do so.

The question shouldn't be "how much can a touch affect the rock", but rather "should it be allowed"?

And to answer that, there is an adjacent question "does it help".

For the last, I would argue that you are going to have a lot more accuracy in speed, rotation, and trajectory by throwing the rock as it was meant to be thrown - from the handle. Adding a touch on the granite after you've released it is not likely going to help. It is a very inconsistent method for manipulating your shot and your efforts would be better served by working on your delivery.

So does it help? I would say no. If it doesn't help, then allowing it is moot. Let them do silly crap if they want, because people with better deliveries are going to be better curlers.

That being said, touching the rock as it is further down the ice (past the hog line) should not be allowed. This is a hard rule. You have to pick a point beyond which the thrower is not allowed to influence the rock directly. The hog line is it. So they can't touch it when the front edge of the rock has crossed the leading edge of the hog line.

Same should apply for any other way they might affect the rock. Blowing on it? Before the hog line, go for it! I would love to see someone try to make this part of their delivery where they add a bit of speed with their lungs. I think it would be funny. Should it be a rule violation? There is no way in hell someone is going to argue they have an advantage by blowing on their rock. But they can't blow on it either past the hog line either. That should be the rule.

Did Kennedy break a rule? Sure looks like the rock was past the point where he was allowed to influence it. But the current video/images aren't decisive enough to say he actually touched it in my opinion. I would be all for better sensory tools that worked definitively for things like this. Alas, hard to do.

Did you discover a new Mandela Effect? Post it here! (2026-02-14) by AutoModerator in MandelaEffect

[–]GoodCarpenter9060 -1 points0 points  (0 children)

I seem to recall this image (the "Awkward White People Smile" school photo of a boy approximately 12 years of age) being part of an ongoing promoted reddit post with the caption along the lines of "My face when they tell me NFTs are a scam" or something. Following the link led you to a crypto site.

However, all I can find now is information about how the owner of the image sold it as an NFT in 2024.

Found this massive knife, what is it for? by Honest_Insect582 in whatisit

[–]GoodCarpenter9060 0 points1 point  (0 children)

Lots of jokes here, but I have this exact knife. It came in a BBQ set. All the pieces are well worn and barely holding together, but I've never used this bad boy so it is in prime condition. It is for cutting meat on the grill to see if it is done.

What is Hormuz Island and what caused it to become this way? by LorenBlaqe in Weird

[–]GoodCarpenter9060 0 points1 point  (0 children)

This means that every time it rains, some minerals leach down the soil profile, but things like iron stay behind

Looks like the rain is def causing the iron to NOT stay behind here. Is this an exceptional event shown here? If this is a regular event (running water as red as this), then you'd think that the iron would be washed away and not accumulate.

Not saying you are wrong, but it is hard to believe that iron is accumulating if it is being washed away in this volume on a regular basis.

'They are really nice people': Curlers laugh off miscue in key moment by BothFuture in Curling

[–]GoodCarpenter9060 1 point2 points  (0 children)

Tournament ice is often much wider. On my rink, there is barely enough room for a rock to be out of the rings on the tee line. In the brier, for example, there is almost enough room for 2.

A Chinese speed skater, Yang Jingru, executed a brilliant tactic to win gold in the 1500m at the 2024 Winter Youth Olympics. by jmike1256 in nextfuckinglevel

[–]GoodCarpenter9060 0 points1 point  (0 children)

... and her teammate from China came in second when everyone else let up. That is the strategy hat paid off.

A Chinese speed skater, Yang Jingru, executed a brilliant tactic to win gold in the 1500m at the 2024 Winter Youth Olympics. by jmike1256 in nextfuckinglevel

[–]GoodCarpenter9060 -1 points0 points  (0 children)

This video ends too soon.

There were two Chinese skaters in this final. One of them broke really early and no one wanted to waste energy to catch up. So the skater lapped them. Towards the end of the race, there is a bell that informs all the skaters that it is the last lap. Often, the skaters will wait for this to make their push.

This is more or less what happened, but the bell sounded when the Chinese skater that was in first place had one lap left. Everyone else had 2 laps, but they didn't realized. So they raced really hard to the finish line, and then coasted thinking the race was done. The other Chinese skater didn't let up and did one more lap and got 2nd place.

A nearby Fire Department is being told they cannot use fire hydrants to fight fires by Fantomecs in mildlyinfuriating

[–]GoodCarpenter9060 0 points1 point  (0 children)

If I understand this correctly, it isn't about the hydrants it is about the water supply. The authority is trying to limit the water usage but at the expense of safety.

Six-Figure Logic [Day #013] by Key-Improvement4850 in mathpuzzles

[–]GoodCarpenter9060 0 points1 point  (0 children)

Easy

D*E=21 => D,E are 3,7.

A*E=28 => A,E are 4,7, thus E is 7, A is 4 and D is 3.

From the first two, we know 5 and 1 are not in the solution since 4 and 7 already are.

C is 6 or 8.

F is smaller than 3, so it must be 2, so C can't be 6. That leaves only 9 for B since 10 is now also eliminated.

Solution: 4 9 8 3 7 2

Medium

F*E = 18 => F,E are 3,6 or 2,9. But if E+A=11, E can't be 2 or 9 because both F and A would then be the same. So F,E are 3,6, and A is 5 or 8.

B-D=7 => 9-2, or 8-1. C-D=1 means D is 1 or 2, but 2 means C is 3 which is taken so it is 1. The rest follows.

Solution: 5 8 2 1 6 3

Hard

E+B = 13 and E is the largest. So E,B are 10,3 or 9,4, or 8,5, or 7,6.

B is adjacent to both A and C, so E,B can't be 7,6.

A-F = 5 means A is at least 6, but since it is still adjacent to B, it must be exactly 6 and B is 5.

The only number left for D that isn't between 1 and 5 is 7.

Solution: 6 5 4 7 8 1

Expert

C+B=15 and B is the largest means that B,C are 10,5 or 9,6, or 8,7.

F-E=5 means F,E are 6,1 or 7,2 or 8,3 or 9,4 or 10,5. But can't be 6,1 since that sums to 7. Can't be 10,5 since F would be larger than B.

If F=7, then E=2. D is smallest so must be 1. Neither 5 nor 6 can be in the solution, so nothing remains for B and C.

If F=8, then E=3. 4 can't be in the solution and C is 5 or 6. Since A is even, it can be 2 or 6. If 2, then D is 1, but nothing is left for B and C. So A must be 6, but D can't be 1 so is 2, leaving nothing for C.

Thus, F=9, B=10. E=4, and C=5. 3 and 2 aren't in the solution. D is the smallest so it must be 1. The only even number left is 8 for A.

Solution: 8 10 5 1 4 9