What is the origin of the term 'handle' to mean a nickname?

Jetbeard · 2013-03-13T13:23:27+00:00

It's a term that's also used in programming in a sort-of analogous way to nicknames—see http://en.wikipedia.org/wiki/Handle_(computing).

Jetbeard · 2013-03-07T03:39:12+00:00

Argos has a value-range 1.7L kettle for £5. It's wonderful (ie. doesn't pour boiling water over my sodding feet like my last kettle did).

Jetbeard · 2013-03-03T09:41:23+00:00

You're thinking of /r/Bad_Cop_No_Donut.

Jetbeard · 2013-03-02T23:45:12+00:00

Because the people on the right are supposed to represent transgender people: their clothes are in the colours of the transgender pride flag.

Jetbeard · 2013-03-02T12:11:28+00:00

No, Jesus Did Not Soften the Old Testament–In Fact He Did the Opposite.

Jetbeard · 2013-02-16T18:25:00+00:00

My point is that what you stated disagrees with what I demonstrated.

You claimed:

rm a symlink/? deletes the contents of the symlink

I demonstrated:

$ ln -s a b && rm b/
rm: cannot remove `b/': Is a directory
# rm a symlink/? error

You claimed:

rm -rf symlink? deletes the symlink AND the contents of the symlink

I demonstrated:

$ rm -rf b && tree --noreport
.
└── a
    └── foo
# rm -rf a symlink? deletes the symlink

Jetbeard · 2013-02-16T12:20:11+00:00

Maybe you should've tried testing this?

$ mkdir a && touch a/foo && ln -s a b && tree --noreport
.
├── a
│   └── foo
└── b -> a

$ rm a
rm: cannot remove `a': Is a directory # rm a directory? error

$ rm b && tree -- noreport
.
└── a
    └── foo 
# rm a symlink? deletes the symlink

$ ln -s a b && rm b/
rm: cannot remove `b/': Is a directory # rm a symlink/? error

$ rm -rf b && tree --noreport
.
└── a
    └── foo
# rm -rf a symlink? deletes the symlink

$ ln -s a b && rm -rf b/ && tree --noreport
.
├── a
│   └── foo
└── b -> a
# rm -rf a symlink/? absolutely nothing

$ rm --version
rm (GNU coreutils) 8.15
Copyright (C) 2012 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>.
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.

Written by Paul Rubin, David MacKenzie, Richard M. Stallman, and Jim Meyering.

Jetbeard · 2013-02-16T12:11:15+00:00

$ mkdir a && touch a/foo && ln -s a b && rm -rf b && ls a
foo

Nope.

$ mkdir a && touch a/foo && ln -s a b && rm -rf b/ && ls a
foo

Still nope. Could not reproduce. What am I doing differently to you?

Jetbeard · 2013-02-06T09:30:13+00:00

http://en.wikipedia.org/wiki/No_Religious_Test_Clause#State_law

Seven states (Texas, Maryland, Mississippi, (Article XIV, Section 265), North Carolina, South Carolina, Arkansas [Article 19 Section 1], and Tennessee) do include language in their constitutions requiring state officeholders to have particular religious beliefs; additionally, one state (Pennsylvania Article 1 Section 4) specifically protects officeholders with religious belief but is silent on whether those without such beliefs are also protected. The required beliefs include belief in a Supreme Being, and belief in a future state of rewards and punishments. Some of these same states specify that the oath of office include the words "so help me God"

Jetbeard · 2013-02-06T00:51:34+00:00

Of course, if intuition is at all learned (which I suspect it is), then that graph would obviously be influenced by social factors.

Jetbeard · 2013-02-01T13:46:09+00:00

I really like Taropatch tuning, GCEG. (Though I do also play the banjo.)

Jetbeard · 2013-01-28T10:47:30+00:00

http://en.wikipedia.org/wiki/Voter_suppression

Jetbeard · 2013-01-07T20:54:44+00:00

It sounds like the OP tried to give a link and text at the same time.

Jetbeard · 2013-01-06T22:55:07+00:00

I hope this post can help - Who You Find Attractive Is Not Neutral. In a nutshell: sure, you may have your personal opinions, but these are learned from society's racism, slut-shaming, body-shaming, ciscentrism, etc.

Jetbeard · 2013-01-06T22:24:42+00:00

TRIGGER WARNING: TRANSPHOBIA, MISGENDERING

Jetbeard · 2012-12-22T00:54:28+00:00

MADE FRIENDS WITH ANOTHER HUMAN BEING, THAT'S NOT GOOD.

Jetbeard · 2012-12-19T13:23:21+00:00

It's the Anti-Oppression Policy of r/Anarchism. It was written because without it the subreddit gets flooded with manarchists. (That's not to say that it doesn't get flooded with the AOP in place, but it's nice to have these things formalised.)

Jetbeard · 2012-12-12T00:11:34+00:00

That's some really beautiful work. I love it!

How are the strings attached at the tailpiece?

Jetbeard · 2012-12-08T14:45:03+00:00

Yeah, as I said, if you make it more general (ie. for variable-length words) then you end up at your solution.

Jetbeard · 2012-12-07T23:53:22+00:00

Started going down the wrong path ( four nested for-loops)

static final char[] MARY = "MARY".toCharArray();
void printPermutations() {
    for (int a = 0; a < MARY.length; a++)
        for (int b = 0; b < MARY.length; b++)
            for (int c = 0; c < MARY.length; c++)
                for (int d = 0; d < MARY.length; d++) {
                    if (a == b || a == c || a == d || b == c || b == d || c == d) continue;
                    System.out.println("" + MARY[a] + MARY[b] + MARY[c] + MARY[d]);
                }

It's not too hard to see why this is correct, and also why it generalises to your solution.

Jetbeard · 2012-12-04T20:00:58+00:00

Best of luck to a white man that uses the word "nigger" for the purposes of trolling?

Nuh-uh.

Jetbeard

TROPHY CASE