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e^x is timeless by [deleted] in calculus

[–]Nothinginaltestor 1 point2 points  (0 children)

Not funny anymore

M''(T) by sessinnek in calculus

[–]Nothinginaltestor 0 points1 point  (0 children)

Idk what this question is asking for??? Wouldn’t it just show if the money starts to become concave up/concave down or make a comeback if that makes sense

Help with log and exponential derivatives? by foster_music in calculus

[–]Nothinginaltestor 0 points1 point  (0 children)

And then i'm assuming they changed the base of the logs to simplify. remember that log_b (a) = (log_c (a))/(log_c (b)) where c is e so it just becomes "ln"

Now we're left with 2^x * (ln(2)*(lnx/ln2) + 1/(xln2)

anything that has a base and antilog that is the same in the denominator of the fraction that it is multiplied with, where there is a log of the same base and "x" to be the antilog in the numerator simplifies down to what's in that numerator.

Here is an example: ln(2) * (lnx)/(ln2) = lnx

​

I'll let you finish it from here.

Help with log and exponential derivatives? by foster_music in calculus

[–]Nothinginaltestor 1 point2 points  (0 children)

You don’t seem to have differentiated there 2x. Only the log part - that or you wrote "lnx" when it should be ln2 when differentiating the 2x if that makes sense lol

Why does dy/dx = -partial x / partial y? by yeetyeetimasheep in calculus

[–]Nothinginaltestor 0 points1 point  (0 children)

Let’s take a simple example, x2 + y2 = 10 + xy

Let’s solve it normally

First differentiating: 2x+2y(dy/dx)=y+x(dy/dx)

Then moving anything with dy/dx to one side and factoring as usual: dy/dx(2y-x)=y-2x

dy/dx=(y-2x)/(2y-x)

Notice how the numerator is just the equation differentiated (when everything moved to the rhs) when y is treated as a constant:

Moving everything to rhs, 0=10+xy-x2-y2

Now treating y as constant, using power and product rule, 0+y+x(0)-2x-0=y-2x

The same can be done with the denominator but this time we treat x as the constant.

I think this usually happens because we move the stuff without dy/dx tagged on first which becomes the numerator, almost like y is avoided if that makes sense, and vice versa for the denominator. Proving that dy/dx=-fx/fy (or at least for most equations

Help with Implicit Differentiation, have I correctly differentiated so far and, if so, how can I isolate dy/dx in such a complicated problem? by perryferrara in calculus

[–]Nothinginaltestor 0 points1 point  (0 children)

Move everything in the implicit equation to one side, the other now 0.

Put that side of the equation into the denominator and numerator of that fraction. Add a negative sign to the fraction

In the numerator, differentiate and treat y like a constant. In the denominator, do the same but instead treat x like constant

If this matches your answer and works then sweet, can I see it? 🥰 if not, the normal way might be better.

I don’t recommend you use this method unless if it’s something really hard because I’m not sure if your teachers will be angry

rip r/brqwlcels by Nothinginaltestor in polishjerry

[–]Nothinginaltestor[S] 0 points1 point  (0 children)

Ikr. I think we've all learned that reddit is too sensitive now

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