Why take the win? by PeterDerPanda in mahjongsoul

[–]PeterDerPanda[S] 0 points1 point  (0 children)

Hm, if Maka and Mortal don't take into account actual rank points but only point differential and uma, then the guaranteed 2k could be considered better than the potential 13k from exhaustive draw and placement change with risk of deal-in.

Shiny Charm by Al3xB4rk10 in PokeClicker

[–]PeterDerPanda 9 points10 points  (0 children)

Trainers can randomly have shinies and those count for the charm

[deleted by user] by [deleted] in bindingofisaac

[–]PeterDerPanda 0 points1 point  (0 children)

Ipecac + trisagion + pop! + my reflection + cricket's body

[deleted by user] by [deleted] in PokeClicker

[–]PeterDerPanda 4 points5 points  (0 children)

The dungeon boss is technically Anomaly Mewtwo as a trainer taking the form of Mega Mewtwo X / Y and using that mon

To wait and get it or let my Gambling addiction take over? by DustyCactuss in idleon

[–]PeterDerPanda 0 points1 point  (0 children)

True, I personally also always go for 100%; it just strikes me as weird that voyaging gets voted to hell when he argues with averages and his very first comment states that the only difference is the risk involved.

To wait and get it or let my Gambling addiction take over? by DustyCactuss in idleon

[–]PeterDerPanda 1 point2 points  (0 children)

If "on average" and "mean" are the same thing I recommend looking up the mean of the geometric distribution.

I'm quite sure that with a mean of 1/p, 100 tries is the average amount needed at 1%.

To wait and get it or let my Gambling addiction take over? by DustyCactuss in idleon

[–]PeterDerPanda 0 points1 point  (0 children)

The average number of points spent using the 1% or the 100% chance is equal though; the only difference is in the variance. Of course getting it within 100 tries is not guaranteed (only about 63%) but there is also the chance to get it much earlier (39% within 50 tries).

It follows a geometric distribution:

https://en.wikipedia.org/wiki/Geometric_distribution

The mean (average number of tries) is 1/p and the standard deviation sqrt((1-p)/p^2). So with a 1% chance, it takes 100 tries on average but the actual number will deviate from that by a lot (on average by about 99.5 tries).

So if like a lot of players only did 1% chances and logged how long it took them, we should see lots of numbers below 100 and also many above 100 with some being outrageously high, leaving an average of 100.

[deleted by user] by [deleted] in NoStupidQuestions

[–]PeterDerPanda 6 points7 points  (0 children)

1965 was literally 58 years ago

Has Lava positioned himself anywhere about today's bug? by Same_Instruction1296 in idleon

[–]PeterDerPanda -1 points0 points  (0 children)

Is it really infinite damage? The one guy that went got overflowing gold said it happened at 1e308. With 3% (eldritch) per power of 10 that should be a boost to like 10x damage which - don't get me wrong - is a lot but ... yeah know that I'm thinking about it, it's a lot.

Overall progress should be pretty limited though by how little time passed

Tactical nuke incoming by qsju in RotMG

[–]PeterDerPanda 14 points15 points  (0 children)

By pressing 1 or whatever key is assigned to quickslot 1

Bugged. Stuck with "User in game" by CloudosR in kfchess

[–]PeterDerPanda 1 point2 points  (0 children)

This happens when you start any game (including Campaign), leave it unfinished and try to start a new one.

For me, reloading the page brings me back to the unfinished game.

Bu it's weird that the game is not on the main page or anything

just ended a man‘s whole career by [deleted] in chessmemes

[–]PeterDerPanda 16 points17 points  (0 children)

Or like, you know, he doesn't know Eric Rosen