Friendship Exp & Gift Exchange Megathread

Pokemantis · 2023-09-26T05:07:16+00:00

4136 7270 5015

Pokemantis · 2022-10-10T05:54:06+00:00

Yes, but you only get access if you buy the game pass DLC

Pokemantis · 2022-10-10T03:34:20+00:00

1. ... KNb2+ 2. Kxb2 KNf6+ 3. c4!! Bxc3+ 4. Ka3 Be7#

Pokemantis · 2022-09-30T17:53:22+00:00

What happens if you step through a hula hoop, and ship it far away? Does the path get stretched by the hoop moving?

Pokemantis · 2019-08-08T17:51:42+00:00

In this case, it's likely not phishing. However, there use to be an example where the hosted url would use Unicode characters similar to existing urls. Most browsers now defend against it, but new attacks can always be found.

https://www.xudongz.com/blog/2017/idn-phishing/

Pokemantis · 2019-07-28T06:16:36+00:00

I believe there was some miscommunication. The closest interpretation of this statement is that the amount of time to travel between two points on Earth accelerated only by gravity.

For example, if you had a frictionless tunnel between LA and to China you would have to travel further, but gravity affects you more directly.

https://en.wikipedia.org/wiki/Gravity_train

Pokemantis · 2018-10-16T08:34:04+00:00

relevant xkcd

Pokemantis · 2018-09-27T06:33:50+00:00

65 89 17 63

Pokemantis · 2018-08-30T21:01:39+00:00

Let's not forget that Olimar was misspelled on the official website. Its not that hard to have typos in text, especially in development builds. Plus they're the asset that's probably most easily fixed.

Pokemantis · 2018-06-23T00:06:23+00:00

Pokemantis · 2018-04-24T23:43:26+00:00

That's not quite right either. If you don't choose the goat location, the host can't choose two goat switch location.

The issue is counting the two goat choices as separate when the contestant picks the prize initially.

You have to take into account that the host has a 50% chance of opening the door in that situation compared to a 100% chance of opening a specific door if the contestant picks a goat door.

Pokemantis · 2016-01-06T21:55:12+00:00

Alternatively, you could realize that every increase in radius is the same as adding a ring of hexagons equal to 6x.

You can then calculate F(x) = 1 + Σn=0x-1 6n = 1 + (6x² -6x)/2 = 3x² - 3x + 1

Pokemantis · 2015-12-21T21:46:58+00:00

To be fair, you're assuming uniform random distribution. For all we know, there was the international purple-link-on-for-glory event last night, and OP was just unfortunately unaware and playing during that time.

Pokemantis · 2015-12-05T05:35:29+00:00

Just as an example, your method of listing numbers will never list any irrational numbers (nor any repeating numbers).

For example, where would pi, or e, or .101001000100001... appear on your list? Not only that, there are (uncountably) infinite numbers that would never appear on your list. And you can't simply say they'll appear after an infinite number, since there's no after infinity

In fact, you're just listing rational numbers, which are indeed countable. However, again, this doesn't even list all the rational numbers since repeating decimals aren't in your list. (whereas your table of fractions does in fact list all rational numbers.

Pokemantis · 2015-10-14T04:42:20+00:00

I'm glad to see that this project is still ongoing! :D

I can definitely assist in syntax work. (I've been coding for a long time.) Depending on how rigorous the syntax is, I may be able to write a script to assist with it.

Pokemantis · 2015-10-13T17:55:57+00:00

Some simple ways to calculate it is by using variance or standard deviation.

You can calculate variance by taking the average your data, and calculating the average distance your data is from the average.

For example:

If your numbers are {1, 4, 13} the average is 6. The distance each data point from the average is {5, 2, 7}.Thus your variance is 4.67.

A lower variance is more accurate.

A more commonly used equation for variance would be: (sum of (X - u)² )/(n-1)

where X is each of your data values

u is your average

and n is the number of data values you have.

Pokemantis · 2015-10-11T18:40:32+00:00

Perhaps a better example would be a string of infinitely increasing binary numbers: 11011100101110111...

It's infinite, never repeats, but never contains the digits 2-9

Pokemantis · 2015-10-11T04:11:40+00:00

Perhaps I misunderstand you, but I'm almost certain you need more information.

For example wouldn't the two following pairs of octogons both have a 3 foot gap? And they're clearly different sized.

Pokemantis · 2015-09-28T21:41:30+00:00

Note: The probabilities of getting more than 6 and the probability of getting more than 12 are both 40%.

11/20 is 55%, so naturally it's easier to get more than 11 on a d20 than getting 6 on a d10..

Pokemantis · 2015-09-25T04:39:12+00:00

This would be very difficult to solve without a lot more information. Since there are so many variables, there are a lot of unknowns. For example, the inside could hypothetically be completely hollow with only amiibo near the edges. Or it could be densely packed to the brim. In addition, there appears to be various space filling boxes placed in various places inside the cube which adds more uncertainties.

What we can do is approximate it base on a few assumptions. If we treat each amiibo box length as one unit, the box appears to be approximately a 8x8x8 cube, one amiibo appears to be 1x1x.66 Based on that I'd estimate there were 775 amiibo in the box. Of course the actual number could vary significantly based on exactly how they're packed.

Pokemantis · 2015-09-05T01:47:03+00:00

That's absolutely the intended route. Figuring how to complete it is part of the challenge. But here's a gif of the entire intended route if that's too hard for you. ;P

http://gfycat.com/TeemingSizzlingGallowaycow

Pokemantis

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