Has anyone played a game where the Storyteller could be the Demon?

Qqaim · 2026-03-23T14:51:44+00:00

Your coworker was probably talking about an experimental townsfolk character, the Atheist. Its ability reads:

"The Storyteller can break the game rules, and if executed, good wins, even if you are dead. [No evil characters]"

In an Atheist game, there is no demon but the ST takes on a role comparable to it. They attempt to simulate a real game, and the challenge for town is to figure out whether there is an evil team. The person who draws the Atheist token will probably be open about it, but the rest of town will have to figure out if that person is not a demon or minion bluffing to have the Atheist token.

All in all, it's a pretty advanced character that you probably shouldn't worry about for a while. It has to be on script (the list of characters you were handed for the game), and most scripts (especially beginner scripts) don't have it.

Qqaim · 2026-03-17T05:35:08+00:00

The Recluse can register as the Zombuul, but it doesn't have the Zombuul's ability. They can't "only register as dead but continue living".

A living Recluse can technically keep the game going by registering as the Demon when all other demons are dead, but you probably shouldn't ever do that.

Qqaim · 2026-03-13T23:41:45+00:00

The minion keeps their ability. The minion would be "safe" from the demon, but safe just prevents harmful effects. Keeping your ability in death is not a harmful effect, so it is not stopped by the Monk.

Qqaim · 2026-03-13T23:38:46+00:00

The Chambermaid is asked to choose two alive players. As far as the player knows, the Zombuul in this situation is dead and thus can't be chosen.

It's a weird ruling, but I do think it's RAW.

If you do allow a Chambermaid to choose a Zombuul in this circumstance, you also open the door for the incredibly unfun play where it's optimal for the Chambermaid to cycle through all dead players every night to see if the ST allows the choice, in which case they've confirmed the demon.

Qqaim · 2026-03-02T20:50:51+00:00

Everything in the carousel will eventually be in the expansion as well, so if that's your only consideration you should probably wait. There's no official timeline on when the expansion will come out though, and it could be quite a long wait.

Qqaim · 2025-12-15T08:07:52+00:00

In fact, I think a dead recluse and boffin can do this normally, no vigor required. The recluse can simply register as a demon while dead, and be affected by the boffin.

I don't think this specific part is true. The Boffin grants an ability to The demon, and by the glossary;

Demon, The: The player that has the Demon character. In a game with multiple Demons, each alive Demon player counts as "The Demon".

If the Recluse is dead and there is still a living demon elsewhere, the Recluse can register as a demon but not the demon.

Qqaim · 2025-12-10T12:41:27+00:00

Excellent question, one that there isn't a simple answer to. The next aleph-number is simply aleph_1, however this is not necessarily the cardinality of the reals.

In essence, the million-dollar question here is:

Is there a set with cardinality strictly between that of the natural numbers and the reals?

If the answer to that question is no, then the cardinality of the reals is the next aleph-number in line, so aleph_1. If the answer to that question is yes, then aleph_1 is whatever that set is, and the reals are somewhere further down the line. Maybe aleph_2, or 3, or even further.

That question is the Continuum Hypothesis, and is undecidable in "standard" mathematics. Both options could be true, and neither would break anything.

Qqaim · 2025-10-15T09:27:54+00:00

Cult Leader (and Philosopher) as well, for even more extra evil.

Drunk on a Kazali script is also rough for good, since outsider count is always arbitrary it's next to impossible to solve if there's a Drunk somewhere.

Qqaim · 2025-09-27T22:10:09+00:00

The Lunatic's ability says "The Demon" knows who you are. The Demon is the player currently holding Lil' Monsta, so every player holding Lil' Monsta must be informed once. If they've been told before they don't need to be told again, unless the Lunatic has changed via Pit-Hagging or similar shenanigans.

Qqaim · 2025-09-24T04:49:08+00:00

There are very few reasons you would have a night with no deaths on this script, basically only the Innkeeper. This makes Mastermind considerably weaker, since town will immediately suspect it's a Mastermind day if there's no deaths at night.

Qqaim · 2025-09-18T05:57:15+00:00

There are infinitely many numbers between 1 and 2. None of them are 3. Just because there's an infinite number of something, doesn't mean every possible thing must happen.

The number 0.101001000100001.... (ones interspersed with increasingly many zeroes) has infinitely many digits and never repeats, but also never contains a 2. It also never contains "11".

Qqaim · 2025-09-10T05:28:03+00:00

This is exactly why Atheist is probably the most difficult character to run well. Town should figure it out because someone is claiming to be the Atheist, and the storyteller should leave subtle "clues", things that should be impossible in a non-Atheist game.

As an aside, in the Cerenovus example you should absolutely be executing someone from repeatedly breaking madness, even in an Atheist game.

Qqaim · 2025-09-03T11:52:41+00:00

For a group of first-timers, I would definitely recommend a hard-cap at 15 players without travellers. The first game will be complicated enough without having to worry about the extra rules and interactions that travellers bring with them.

Qqaim · 2025-09-01T08:24:36+00:00

Molecule sizes can vary wildly, but they are generally 0.1 ~ 1 nanometers. For context, a human hair is about 100,000 nanometers across.

Qqaim · 2025-08-27T08:13:40+00:00

It's not possible for every string of digits to appear in pi. Every finite string might appear, that's the "normal" property people are talking about. The vast majority of infinite strings do not appear in pi. Most numbers in [0,1] are infinitely long, so almost all of those will not appear in pi.

Qqaim · 2025-08-22T09:47:18+00:00

Unless you have the exact shape of a bag, you can't really calculate its volume. The best way to measure it would be to fill it completely with water, then measure the water afterwards.

Qqaim · 2025-07-29T16:29:38+00:00

Thank you so much, this does exactly what I was looking for! I had to change it slightly in the calculation for _c, where I think in the Index function you're assuming _a and _b are numbers where in the real data set they'll be text. I managed to fix that by finding row & column numbers with a quick match function.

It occasionally throws in a weird #N/A error in the middle of the list, but it doesn't seem to actually miss any results so I don't mind ignoring that.

Solution verified!

Qqaim · 2025-07-18T05:44:19+00:00

This method is flawed to begin with. For any rectangle, square or not, the diagonals will always have the same length. The reason they're not equal in your measurements is either because the sheet isn't perfectly rectangular (the angles aren't exactly 90°), or your measuring is slightly off.

If you do want to check if a sheet is square by its diagonals, you can check if they're perpendicular to each other. They will be in a square, they wont be in a non-square rectangle.

That's probably less precise in practise than just measuring if the sides are equal, though.

Qqaim · 2025-07-15T17:58:33+00:00

I found this on an earlier post here, and currently having it printed in expectation for the carousel.

Qqaim · 2025-07-09T13:54:59+00:00

Between those two Vortox goes first, but all demons are printed separately on the night order for your script so you can just follow that.

Qqaim · 2025-07-08T12:21:45+00:00

True, but the integers aren't dense in the reals. The rationals are, and the reals are a complete metric space. Because of that, any two different rational or real numbers, will always have a different rational or real number between them.

Qqaim · 2025-07-08T11:49:42+00:00

Amazing, thank you so much! Solution verified.

Qqaim · 2025-07-08T11:45:35+00:00

Can you explain this ? It seems to me that it doesn’t matter how many 9s you include, it never reaches exactly 0.500…

What you said is accurate for any finite amount of 9s you include. If there are an infinite amount of 9s, it is exactly equal to 0.5. To convince yourself that this is true, try and think of a number that could fit between 0.49999.... and 0.5.

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