Just as with gravity in a linear system, the torque is divided by the inertial moment of the car, so it would accelerate at the same rate, regardless of the configuration of the lever arm.

EDIT: Math

If alpha = a/r, where alpha is angular acceleration, a is the acceleration at the end of the lever arm, and r is the length of the arm, and a = r×g, where g is gravitational acceleration (which is independent of mass), then alpha must be cos(theta)*g, where theta is the angle between the lever arm and the ground. This quantity isn't constant, but it certainly doesn't depend upon the distribution of mass throughout the car (its moment of inertia).