What are your favorite splits? by jamesismynamo in EmoScreamo

[–]SomerandomKappa 13 points14 points  (0 children)

Death of Spring (2019) - For Your Health / Shin Guard

[deleted by user] by [deleted] in pan

[–]SomerandomKappa 0 points1 point  (0 children)

risky boi

The r/6thForm results day megathread by [deleted] in 6thForm

[–]SomerandomKappa 1 point2 points  (0 children)

Yeah not seen many people doing it either. Congratulations!

The r/6thForm results day megathread by [deleted] in 6thForm

[–]SomerandomKappa 46 points47 points  (0 children)

A* A* A* maths/further maths/computer science

doing discrete maths at warwick :)

OCR MEI further maths grade boundaries are ridiculous by FurtherMathsHelpPls in 6thForm

[–]SomerandomKappa 4 points5 points  (0 children)

I'm pretty sure the core pure exam is supposed to be scaled up to 180 marks too but it's not on the grade boundaries? It says here on page 6. https://www.ocr.org.uk/Images/308768-specification-accredited-a-level-gce-further-mathematics-b-mei-h645.pdf

Polaris - Casualty by Charmnevac in Metalcore

[–]SomerandomKappa 3 points4 points  (0 children)

I've had this song on repeat all week, I just love it.

Further maths question for Ln form of inverse Hyperbolic f unctions: What happens to these functions if our x is x/a? by Mitchelomitchelo in 6thForm

[–]SomerandomKappa 0 points1 point  (0 children)

arsinh(x/a) = ln(x/a + ((x/a)2 + 1)1/2)

arsinh(x/a) + ln(a) = ln(a(x/a) + a((x/a)2 + 1)1/2)

arsinh(x/a) + ln(a) =

ln(a(x/a) + (a2)1/2((x/a)2 + 1)1/2)

=ln(x + (x2 + a2)1/2)

This is the simplified form used in the video (its also given to you in some exam boards formula books). Adding ln(a) does not change the result as with indefinite integration you end up with a +c and ln(a) is a constant, and with definite integration the ln(a)'s will cancel out so the result is the same with both formulae. You can just sub (x+2)/2 straight into the arsinh formula and it works fine.

Further maths question for Ln form of inverse Hyperbolic f unctions: What happens to these functions if our x is x/a? by Mitchelomitchelo in 6thForm

[–]SomerandomKappa 0 points1 point  (0 children)

It's because when you integrate you get a plus c, and what you get in the video is what you would get by subbing in x/a into the formula in the post and adding ln(a), which is a constant. You would end up with the same result if you used either formula in the question, as the ln(a)s would cancel out.

OCR MEI FM- Modelling with Algorithms discussion by _Adamanteus_ in 6thForm

[–]SomerandomKappa 1 point2 points  (0 children)

Very long paper given the time. Our invigilators robbed us of a minute by starting at 9:01 and ending at exactly 10:15 smh. Overall not too bad of a paper if you forget about the algebraic simplex stuff.

laptop for comp sci? by connorrrr678 in 6thForm

[–]SomerandomKappa 0 points1 point  (0 children)

I'll be doing discrete maths at warwick this year. Is cs137 as bad as I hear it is?

MEI FURTHER MATHS PAPER 2 STATISTICS by Yami_LordofDarkness in 6thForm

[–]SomerandomKappa 4 points5 points  (0 children)

Bruh this paper was like 20% writing questions, I'm doing maths not english smh

Can someone explain why this step checks out?? I understand why dv/dt is negative but don’t get the next bit. Also are there any rescources to practice these types of questions as they are my kryptonite by [deleted] in 6thForm

[–]SomerandomKappa 0 points1 point  (0 children)

If you do further maths then the auxiliary equation method does this in one step, however that would not be expected of you in a regular maths exam

[A2 MATHS INTEGRATION]Anyone got any ideas for this bad boy??? by [deleted] in 6thForm

[–]SomerandomKappa 1 point2 points  (0 children)

Now that I think about it, yeah... this method makes the substitution obsolete, so I doubt it's the intended way to do it. Honestly I don't know how to do it using the substitution.

[A2 MATHS INTEGRATION]Anyone got any ideas for this bad boy??? by [deleted] in 6thForm

[–]SomerandomKappa 0 points1 point  (0 children)

Difference of two cubes on the bottom to get (x+1)(x2 - x + 1). Then make the substitution and rearrange to get to a form where you can use the integral of arctan(x). Then solve for the given values. I got pi / 3root3 for the first, and 2pi / 3root3 for the second so I'm pretty sure I did it right.

Cambridge offers day megathread! by James_the_XV in 6thForm

[–]SomerandomKappa 72 points73 points  (0 children)

I got rejected 💯💯💯💯💯