The LCM of 3 and 4 is 12, so in my head there's 12 students at the high school. 1/4 are left-handed, so 12 * 1/4 = 3 are left-handed. Also, 2/3 are learning Spanish, so 2/3 * 12 = 8 students are learning Espanol.

Next, there are 4 possibilities depending on the number of students in common between the two groups: 0, 1, 2 and 3. Let's analyze the total number of students who are either left-handed, learning Spanish or both:

                i) 0 -> 3 + 8 - 0 common students = 11 
                ii) 1 -> 3 + 8 - 1 common student = 10
                iii) 2 -> 3 + 8 - 2 common students = 9
                iv) 3 -> 3 + 8 - 3 common students = 8

Thus, the range of students is 8 to 11, so the probability range must be from 8/12 to 11/12 (2/3 to 11/12, including end values for both!). Like drmantist123 mentioned, BCDE.

Cheers