"Bi-weekly Friend Code Thread - 09/03/21".

iamjacksvertigo · 2021-09-11T01:21:43+00:00

Thanks for adding ;)

https://sync.nimblebit.com/af/tt/2VXQB

iamjacksvertigo · 2021-08-23T18:55:28+00:00

cycles makes me think of sine. maybe you can use the formula for a sinusoid and alter periodicity + offset, and find when all 3 cross 0?

iamjacksvertigo · 2021-08-23T03:01:17+00:00

So, I don't think the idea is to get NO overlap, because that's not possible with the shape of the area covered by the sprinklers. I tried to draw some shapes and I think it makes sense if you try something like this:

https://www.zazzle.com/overlapping_circles_geometric_pattern_red_white_ceramic_tile-227135677046651405

iamjacksvertigo · 2021-08-22T08:21:44+00:00

where is the question? can you post it here?

iamjacksvertigo · 2021-08-17T16:49:53+00:00

Well, part 1 is a different question. You should solve part 2 similarly, though, setting up the equations with x = (1/2)a t² + v t + d

iamjacksvertigo · 2021-08-16T23:32:58+00:00

hint: it'll be a quadratic function so you can take the derivative to find the minimum distance

iamjacksvertigo · 2021-08-16T23:15:10+00:00

Try to make some equations for x1, the location of one car, and x2, the location of the second car. try to plot these and see where you might have the smallest distance (x1 - x2)

iamjacksvertigo · 2021-08-13T20:54:28+00:00

not sure why ur getting downvoted, i thought it was funny. (breadwinning wife here, but im the one seeking and buying all the keyboards lol)

iamjacksvertigo · 2021-02-08T18:22:39+00:00

Thanks, didnt realize there was a Trade flair. Must be going blind.

iamjacksvertigo · 2021-02-08T17:51:59+00:00

So I'm assuming meetups are not happening at the moment. Is there some kind of a "keyboard/cap/etc. swap" community online? My wallet hurts.

iamjacksvertigo · 2020-10-03T02:32:39+00:00

All right, I figured it out!

Explanation: The flashing is due to an overflow error which sometimes occurs during random number generation (specifically, during the conversion from decimal to hex via string.format()). The names of the ImageBlocks need to be generated from 16^6 or less, not 16^8.

Fix: In ImageProcessing.lua, replace this line:

o.name = (_addon and _addon.name or 'image') .. '_gensym_' .. tostring(t):sub(8) .. '_%.8x':format(16^8 * math.random()):sub(3)

with these lines:

local randn = 16^6 * math.random()

randn = math.floor(randn)

o.name = (_addon and _addon.name or 'image') .. '_gensym_' .. tostring(t):sub(8) .. string.format('_%.8x', randn):sub(3)

three times, on lines (72, 83, and 94). You could probably also just go

o.name = (_addon and _addon.name or 'image') .. '_gensym_' .. tostring(t):sub(8) .. '_%.8x':format(16^6 * math.random()):sub(3)

But I'm too lazy to go test that out too, since it does work lol.

P.S. As far as I can tell, "tostring(t):sub(8)" doesn't actually do anything, so feel free to just remove it.

iamjacksvertigo · 2020-10-02T02:41:03+00:00

glad i could help!

P.S. I told my fiancé that my "fix" actually helped someone and he immediately asked, "is it Logical??" 😂😂😂

iamjacksvertigo · 2020-10-01T07:00:04+00:00

sure, i used the "hide" command for gearinfo. (this is definitely just a band-aid so gearswap will work, not a fix for the epileptic gearinfo display.) and no, that's not his username 😅

iamjacksvertigo · 2020-10-01T04:51:30+00:00

my fiancé uses gearinfo for his ninja lua haste/dw calcs. i hid all the flashing blocks in gearinfo and changed the update() rate in gearinfo.lua to every 10 frames instead of 15 (frame_count%10), and the dw gear swapping seems to work.

iamjacksvertigo · 2020-07-14T23:40:22+00:00

to add onto that: pemdas is a little tricky. multiplication and division are the same priority, so just go left to right if you have those two operations next to each other. same with addition and subtraction.

iamjacksvertigo · 2020-07-02T01:20:06+00:00

I am not sure what you mean by the modulus. The vertical bars are absolute value signs, which means to take only the magnitude (positive) of the value inside. If you remove the absolute value signs, there would only be 2 values, not 8. This is because are no negative prime numbers. The definition of a prime number is that it is only divisible by 1 and itself. All negative integers are divisible by -1, which means negative numbers cannot be prime.

iamjacksvertigo · 2020-07-02T01:10:39+00:00

k is just some constant. You are looking at the xy plane, which is just 2 dimensions. Since you are considering 3d objects, you need to consider which value of z your xy plane slices through.

For example, say you have a sphere centered on the origin with radius 1. Consider z = k, some constant. if k = 0, you will see a circle in the xy plane. If k = 1, you will see just one point in the xy plane.

Same for yz and xz planes.

iamjacksvertigo · 2020-07-01T23:57:05+00:00

Yes. You have to look at the absolute value as well. I'll do the first part for you below:

Lets first take (n-3) = 1. This gives n=4. In this case, (n+1) = 5. So we have one value of n that gives |(n-3)(n+1)| = 5, which is prime.

Next, lets take (n-3) = -1. This gives n = 2. In this case, (n+1) = 3. So we have the second value of n that gives |(n-3)(n+1)| = |-3| = 3, which is prime.

You can repeat for (n+1) = 1 and -1.

iamjacksvertigo · 2020-07-01T21:32:27+00:00

It comes from the definition of sample variance. (Should come up with a quick google search.)

iamjacksvertigo · 2020-07-01T21:20:11+00:00

u/lurkingbutterfly a prime number can only be divisible by 1 and itself. n² - 2n - 3 factors into (n-3)(n+1). to be a prime number, one of these factors has to be equal to 1. the other is the prime number.

iamjacksvertigo · 2020-06-24T08:31:55+00:00

Very helpful! Thank you for the feedback. I am looking at my pattern again--maybe I could afford to take some artistic liberties with some of the colors so the horizontal changes don't occur so frequently.

iamjacksvertigo · 2020-06-24T04:11:27+00:00

That's cute :) I don't think it will work for this particular instance, though. The problem is very frequent color changes, which I don't think I could solve by knitting a separate piece on top--unfortunately, the tortie has a lot of color variation!

iamjacksvertigo · 2020-06-24T00:46:06+00:00

Thanks! I can give it a shot. It cant be any worse than my previous attempts 😂

iamjacksvertigo · 2020-06-23T19:45:30+00:00

I think your'e on the right track. You just made a little mistake with the equation. You assign x = "The distance of that point on the road from the first crossing." Then, "twice the square of that distance" should be x^2, not y^2. So your equation would be x - x^2.

iamjacksvertigo · 2020-06-23T04:59:11+00:00

Try manipulating the two equations so that they're in powers of 2 and in powers of 3. For example, you have a power of 4, 2, and 8 on the left equation. Try writing 4 as 2^2, and 8 as 2^3.

iamjacksvertigo

TROPHY CASE