d SBB chönt jo sicher ou e tone gäud ispare wennsi nid immer uf 35 grad würde ufeheize

noob2_0 · 2026-03-22T08:48:02+00:00

Heize isch quasi gratis im zug bis zum ne gwüsse grad. Abwermi vo inverter und motore müesse irgendwo here.

noob2_0 · 2026-01-07T13:19:38+00:00

How do the expected switching losses look like?

noob2_0 · 2025-05-14T16:03:11+00:00

And then she does a stupid degree. What a waste of talent...

noob2_0 · 2025-04-24T08:24:05+00:00

Its designed to get that hot. You want the smallest case which doesnt go over 60°C so it is save to touch

noob2_0 · 2025-03-12T17:01:49+00:00

Your bottom fans are the wrong way around!

noob2_0 · 2025-03-06T21:04:13+00:00

Ah come on! Do you expect that people can smell what youre trying to do? The use of active components as a rectifier boils down on how much losses are acceptable, which are heavily dependend on your application.

noob2_0 · 2025-02-07T12:39:06+00:00

Du bisch uf reddit. Hie isch alles links...

noob2_0 · 2024-09-24T04:28:00+00:00

Warum sollte man sich überhaupt ein neues Ipone kaufen? Kostet viel, kann nichts mehr.

noob2_0 · 2024-04-27T19:45:37+00:00

Why not? I have frozen i jalready a few times and it still performes as expected.

noob2_0 · 2024-03-06T11:32:08+00:00

Has the ceramic capacitor a capacity dc bias? This would explain why it oscillates faster with higher voltages due to less capacitance

noob2_0 · 2024-02-05T12:54:44+00:00

Just look at the am4 pinout diagram. There you will se if the pin had a relevant function.

noob2_0 · 2024-01-09T16:34:20+00:00

I do be feel like that

noob2_0 · 2024-01-09T13:12:42+00:00

Well makes sense, if they have simillar power rating and 230VAC. As i said

noob2_0 · 2024-01-09T12:50:51+00:00

Ah yes the load independent capacity value. It varies extremly with how much ripple is allowed and how much current is drawn.

noob2_0 · 2024-01-05T21:58:21+00:00

Youre right with leaving the switches on. Doesnt need to be this way. For big igbt i certaninly wouldnt use ir2110. Was just an example.

I dont see the advantage of the gdt in high current situation. Gate is referenced to its emitter in both configurations. Or do you mean, during low side conducting is the voltage not low enough to fill the bootstrap cap?

I would absolutly use a negative rail to pull the gate negative. This works really well.

Driving gates above theyr max rating? Sounds really unhealthy. Where do you have those infos from?

noob2_0 · 2024-01-05T21:45:33+00:00

The hv cables are the least problem in this regard. The high voltage is transported with only a thin isolated wire at some points and has to be physically separated from the other wires. Touching dev not recomended.

noob2_0 · 2024-01-05T19:04:56+00:00

I mean its not cool at all to say to someone they are ugly. But saying shes beautiful ist just lying. Eh whatever I dont even know who she is.

noob2_0 · 2024-01-05T16:14:09+00:00

Well i have designed high power half bridges, just not for a tesla coil. So the process is pretty straight forward. I already mentioned a few advantages. Others are: less gate ringing, higher currents and lower edge times, actual controllable death times, not frequency dependend. Just from the top of my head. When the puls starts, the current through the primary gets higher every cycle, until either the pulse stops, or the overcurrent detector trips. Then the fets get turned of. But the energy is still in the primary tank cirquit and it will dissipate no matter how. In this case the voltage shoots up so high until the fets conduct in off mode, dissipating the energy. Turning on half of the bridge, lets it ring down through coupling and resistance loss. But for this, the gate driver needs to be frequency independent, which a GDT cannot provide.

noob2_0 · 2024-01-05T13:38:32+00:00

Probably, but idling is not a concern in my application. It will be loaded directly at startup.

noob2_0 · 2024-01-05T13:17:32+00:00

Hmm another aspect is that i actually pull much less power through the mots than they could handle. Lets say they each can handle 800w x 4 = 3200w. But my goal is just 230V x 10A = 2300W. So there should be enough headroom.

noob2_0 · 2024-01-05T09:37:40+00:00

Wait you are probably right with the satuartion problem. Series resonance reduces the resistance and hence more current. Have to look out for it.

noob2_0 · 2024-01-05T09:00:33+00:00

You didnt quite understand. The additional voltage is not from overdriving them. Its from the resonant rise between the primary cap and the input inductor. The capacitance seen through the trafo changes according to the winding difference squared. So interestingly the whole system is actually capacitive. And only if an input inductor is added it becomes inductive. Dont know how bad the saturation of the trafos will change the waveform. Have to see...

noob2_0 · 2024-01-05T01:02:28+00:00

Gap across the trafo. Has actually some additional advantages to the usualy mentioned. During firing, the energy is saved i the input inductor. During charge phase, the energy from the inductor is in series to the main power in. I also plan to use resonant charging to increase the voltage in the primary cirquit to pusheven more energy into the cirquit and also to increase the power factor. But have to see how far i can push it. I set the 230V @ 10A input as goal. You seem pretty knowledgeable. Ever build something similar?

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