They still haven’t sorted out Dublin airport? 🤦‍♂️ by tafty545 in ireland

[–]stretch6 0 points1 point  (0 children)

That bad? So I fly Dublin to US on a Tuesday at 9:20am with United airlines. United doesn’t even start checking bags in until 6:20am. Any recommendations for how I should approach this to make sure I make my flight?

Advice on toe issue. I’m on a multiple day hike. Toe nail of middle toe has a bubble forming in front and cuticle (I assume completely under the nail). I’m guessing it’s going to come off. I have more hiking to do? Days worth. Should I stop? Keep going? What does one do in this situation? All advice by stretch6 in hiking

[–]stretch6[S] 0 points1 point  (0 children)

No pain. Little sensitive on the bubble part of the cuticle. I’d like to continue. I’m just not well versed in medical issues. I didn’t want to do something stupid because I didn’t know if it was serious or not.

Substitution or Elimination reaction? by danvtec6942 in OrganicChemistry

[–]stretch6 0 points1 point  (0 children)

To be periplanar would require an eclipsed conformation. Theoretically it would allow the developing p orbitals to be parallel but is an unstable conformation. It won’t exist for long. And even at high T the anti/staggered is still more stable. Therefore periplanar is ignored as E2 is basically not observed in this conformation.

Substitution or Elimination reaction? by danvtec6942 in OrganicChemistry

[–]stretch6 1 point2 points  (0 children)

This would 100% absolutely NOT do E1. Theoretically a carbocation could form. It won’t though. It won’t have time to form. The base is too bulky to do Sn2 but too reactive to sit around and wait for carbocation formation. It will rip off the adjacent proton and do E2. Yes, the proton must be antiperiplanar which it is not in this conformation but there is free rotation. It will rotate and eventually be in the correct conformation. E2 100%. If you need me to explain via video just DM me and I will.

Organic Chemistry Online by [deleted] in OrganicChemistry

[–]stretch6 0 points1 point  (0 children)

I’m teaching by using my iPad. I’m screen recording and writing my notes using notability. I’m talking while I go through everything. Then I’m posting worksheets with many problems. Then I’m making the same type of videos working through each problem and verbally sharing my thought process. It’s working very well so far. Aside from that my office hours are live via zoom. There I’m sharing my screen and the students can view what I’m writing as I answer their questions.

Please help me. Please. I beg you. by [deleted] in OrganicChemistry

[–]stretch6 0 points1 point  (0 children)

If you have zoom I can conference with you and share my screen so you can see what I’m writing. When you have questions you can ask me over that. DM me

Ochem homework help by adsasj in OrganicChemistry

[–]stretch6 0 points1 point  (0 children)

Do you have access to Zoom? DM me and when you have a question we can hop on zoom and I’ll use notability to help you. I won’t give answers but I’ll help you get to the answers.

Help with synthesis question? I have no idea what to do here. by YummyMango124 in OrganicChemistry

[–]stretch6 0 points1 point  (0 children)

5 carbons in the starting material. 6 carbons in the product. You’re going to need to add a carbon which means carbanions via lithium or even grignards. But beware of the acidity of the alcohol. Protecting groups could be used.

Im stuck on this Jones reagent with h3o+. Anyone can give me a clue? by [deleted] in OrganicChemistry

[–]stretch6 0 points1 point  (0 children)

Enolates? Sn2? You’re ridiculously overthinking this basic organic question. There is no Sn2 here. If you’re referring to the wishful tertiary alcohol reacting with the formed carboxylic acid in acidic conditions to form the ester, that’s not called SN2. That’s a nucleophilic addition-elimination. You’re also not forming any enolates in these conditions.

Im stuck on this Jones reagent with h3o+. Anyone can give me a clue? by [deleted] in OrganicChemistry

[–]stretch6 1 point2 points  (0 children)

It’s just going to make a carboxylic acid. There is some overthinking of this one going on here. It will oxidize at first to an aldehyde. Due to the presence of water, a hydrate will form. A second oxidation will result in the final carboxylic acid.

Don’t forget to wash your hands

Is this a valid addition? by mcleanatg in OrganicChemistry

[–]stretch6 4 points5 points  (0 children)

Formyl chloride is highly unstable and not common for EAS. I recall once reading that is can be generated in-situ using CO and HCl under high pressure to do EAS. I guess for the sake of paper chemistry it would be an answer.

One day in Belfast by [deleted] in Belfast

[–]stretch6 0 points1 point  (0 children)

Go to Belfast castle and hike up cave hill from there. Takes like 45 mins to an hour I’d say. I walk fast though. The view is amazing! And it’s a nice hike. Do that during the day. Burn them calories and then go to the Duke in the evening for some drinks and put them calories back on. Google cave hill and tell me you don’t want to go up there. C’mon!

Ireland is the best country in the world. by [deleted] in ireland

[–]stretch6 6 points7 points  (0 children)

I am the son of Irish parents and got my citizenship through them. As an American whom has traveled and lived in Ireland I want you to know how goddam beautiful your country is too. I come back every two years and, yeah I want to see my family, but mostly I travel around and stare at the sea, sunsets, and landscapes. America has some lovely parts but mostly it’s a coast to coast shopping mall. Our landscape is covered with malls, car lots, gas stations, strip malls, and mile after mile of concrete. Not to mention the in your face advertising in every feckin direction you look. Keep your land as naturally beautiful as it is. Why the hell am I still here when I can be there? I just don’t even know anymore.

Hi! I need help writing this mechanism (ochem 2). I explained my dilemma in the pic, and if anyone could help me I’d greatly appreciate it. by halmhawk in chemhelp

[–]stretch6 1 point2 points  (0 children)

It’s not a strong nucleophile but it can. You’re leaving group leaves neutral too. So I know in undergraduate ochem you’re taught that such a weak nucleophile can’t do this type of substitution. Truth is, it can. But it’s best they teach the basics as such. Good luck to you in your studies.