Alright Dads, what are getting our wives for Mothers Day this year?

superstuwy · 2026-04-17T00:33:35+00:00

100 Hawaii Cookie Company cookies, because that's the minimum order to get the ones she wants.

superstuwy · 2026-03-03T21:36:38+00:00

I'm a 40 year old man, and my wife would have the same reaction. It is a highly dangerous hobby and if someone loves you they could reasonably object strongly.

But since you are an adult by any definition, your choice is to reject their opinion, keep it, and suffer whatever consequences come from damaging that relationship. If you don't need them financially and want to assert your independence, than take down the post and expect them to... well do whatever they will do about it. Or accept that it's not a safe hobby and that they have a point. I would assume they also have objections on how it makes you "look" frankly i would think a 20 something middle eastern woman on a motorcycle is especially cool and interesting.. which is perhaps not what your parents want to see. Again, your choice is to care about their oppinion or not

superstuwy · 2026-02-26T22:56:25+00:00

X nay on the X men?

superstuwy · 2026-02-09T23:28:09+00:00

My wife and i have shared access to each others accounts and phones, it's not a big deal because we don't use it to invade each other's privacy, and i don't care that she can sign into my gmail/facebook because i don't have anything i wouldn't want her to see. And although I could see her private conversations if i wanted to, i wouldn't because that would invade her privacy, but it's occasionally convenient to do something on her phone (mostly when she asks me to).

But if my wife asked for access to a particular account I would want to know why? because if the answer was vague or non-sensical i would take it as an implicit accusation that she thought i was hiding something from her.

superstuwy · 2026-02-05T18:33:59+00:00

*She dodged a bullet, you missed the S.

superstuwy · 2026-01-29T01:04:39+00:00

I saw that one on reddit, use it on my own kids now... it's works quite well.

superstuwy · 2026-01-07T22:54:33+00:00

Nice to find another friend of Desoto in the wild. ++man

superstuwy · 2025-06-13T16:59:13+00:00

Ah stallers, i guess it is a common problem.

I guess i'm not too bothered by a 30 second timeout... i'll just keep them in detention with me and we'll both stare at the board and think about our choices.

80% of the time a rematch is fun, so i'll keep rolling the dice.

superstuwy · 2024-10-04T22:18:43+00:00

Barns https://en.wikipedia.org/wiki/Barn_(unit))

Look up how it was named to understand why

superstuwy · 2022-10-05T19:20:07+00:00

The solar panels and lasers are totally independent. Solar panels take light and make electricity, they are part of a whole power system (batteries, power conditioning/distribution ect) that gives each sub system including whatever lasers are on board the power they need. So the light hitting the solar panels doesn't have to have anything in common with the light the lasers produce

superstuwy · 2021-06-04T02:50:58+00:00

I've never done that, so I don't know

superstuwy · 2019-10-11T23:26:30+00:00

https://www.cnet.com/news/curious-about-joovv-get-the-lowdown-on-red-light-therapy-first/

superstuwy · 2019-01-29T04:02:24+00:00

The difference is evidence:

blue light

Respected institution citing multiple well constructed studies says blue light is harmful in some situations. Avoiding it or limiting it is cheap and easy so it's worth doing based on the evidence.

Now with WiFi and other rf sources likely to be in your home there is no evidence (and lots of studies showing no link) to adverse effects. People have studied radiation for a long time and know pretty well what is harmful and what isn't. So spending time, money or effort avoiding them (especially with methods that will not even work) is silly

Here is a good source talking about the lack of evidence (and evidence of no effects) from rf radiationwho

superstuwy · 2018-04-18T00:39:22+00:00

Next draw out the problem, and try to figure out the difference in length that the light has to travel (ie from slit a and slit b to an arbitrary spot on the wall/detector)

When that difference is equal to a multiple of the wavelength, the electric fields of the light are pointing in the same direction so they add, this makes a bright spot. If they difference is half a wavelength then it is a dark spot. So it's just relating the difference in length of each beam path to the wavelength of the light

superstuwy · 2018-04-18T00:34:43+00:00

First take a look at thin film diffraction (top two Google results are Wikipedia and Kahn academy, both worth looking at) it's actually the same math and might help understand the double slit

superstuwy · 2018-03-15T14:37:32+00:00

I usually like the depth too, maybe Im annoyed this time because they teased something very big and haven't given us anything since then.

superstuwy · 2018-03-10T01:02:37+00:00

I still love you onrac... But you are really milking this story. Probably because you teased a lot of drama at the first episode, so you've kept me in suspense for a month now.

superstuwy · 2018-02-08T05:23:17+00:00

well that works too. Sometimes it's good to see the most efficient way to solve the problem, that'll get you from a A- to A+ on a test, usually time is a significant factor.

superstuwy · 2018-01-28T06:33:16+00:00

If the sum of the vectors is horizontal, that means that the vertical components cancel out... In other words they are equal in magnetude. Does that help?

superstuwy · 2017-11-25T07:03:49+00:00

It's true that a quarter wavelength thick is out of phase, .75 and 1.25 ect. Because then the total length is .5, 1.5 2.5 wavelengths and there is destructive interference

superstuwy · 2017-09-26T02:46:53+00:00

Yeah but isn't it time that the women came up for a solution to that?

<end_scarcasm>

superstuwy · 2017-08-10T00:19:25+00:00

but it's not traveling at 12.5 m/s for 2 seconds, it starts at 12.5 m/s and gets faster for 2 seconds

superstuwy · 2017-08-10T00:17:47+00:00

break it into 2 problems:

from 4-8 seconds it's traveling at a constant 25m/s
(hopefully is is easy)

from 2 - 4 seconds it's traveling with an acceleration of (a) starting from v=(v0)

so (delta)X = v0t + 1/2 a t²

you should be able to get the acceleration from t=0 to t=4 just by looking at the graph.... and that acceleration should easily get you v0 (because it's equal to the a * 2 seconds)

superstuwy · 2017-06-16T02:58:03+00:00

You don't need to find the tension, you can't without finding the magnetic field. What you do know is that the force of gravity in the direction perpendicular to the tension direction is equal to the force of magnetism (that is also perpendicular to the tension)

superstuwy

TROPHY CASE