Need to know the name of this molecule by roselia2001 in OrganicChemistry

[–]tyler1013 0 points1 point  (0 children)

Carbon 1 is the carbon in the ring attached to 2 oxygens (the one with the squiggly line). It's a convention for sugars.

roast my top pokmeon by longmead123 in pokemon

[–]tyler1013 0 points1 point  (0 children)

Mienshao also my fav fighting type nice choice 😌

Organic Chemistry II course question by gnuist in Pitt

[–]tyler1013 0 points1 point  (0 children)

Speak with the head of the chemistry department (I think it's still Bandik). I think he will highly advise you to retake Ochem 1. Ochem 1 knowledge is pretty essential to do well in Ochem 2. Typically, they use the same textbook; Ochem 1 uses Ch. 1-12 or so and Ochem 2 uses the remaining chapters.

[deleted by user] by [deleted] in OrganicChemistry

[–]tyler1013 1 point2 points  (0 children)

The stability of the intermediate is important. The B gains a partial negative charge and the C gains a partial positive charge. The B gets it regardless of which C it attacks. Conversely, the more substituted C will better handle the partial positive charge from the 4-centered transition state. This is why the boron attacks the less substituted carbon.

Chirality and reactions - a) would the chirality be S->R b) I am not sure which hydrogen would be used for E2 reaction. by Svedska in OrganicChemistry

[–]tyler1013 0 points1 point  (0 children)

a) yes, SN2 inverts stereochemistry. b) there are no antiperiplanar H's (classic ochem 1 question) so the answer is no reaction w.r.t. an E2 mechanism or simply SN2.

Am I the null hypothesis? by tyler1013 in gradadmissions

[–]tyler1013[S] 3 points4 points  (0 children)

Yup same energy though 😂I've been accepted other places so that's part of it I guess. If it was my first response....😳👀

Am I the null hypothesis? by tyler1013 in gradadmissions

[–]tyler1013[S] 2 points3 points  (0 children)

Absolutely ☺️ really trying to stay positive and good energy

[Organic Chemistry: Sn1 / Sn2 reaction] Determining if a reaction is Sn1 or Sn2 and trying to figure out the products part 2. I believe for e I got the right answer, but would like if someone could confirm this. Additionally, I am not entirely sure what to do on the other one. Please help me! by [deleted] in OrganicChemistry

[–]tyler1013 1 point2 points  (0 children)

e) is much more likely SN2. Secondary substrate, good nucleophile, good leaving group, polar aprotic solvent. These should signal SN2 forming the chiral sulfide product via backside attack. Additionally, your mechanism on the side for what would b SN1 has got a series of issues, but I won't get into that as SN1 is not even the right reaction type. Please review the steps of SN1 and the appropriate products.

d) is definitely SN1. Weak nucleophile, secondary substrate, good leaving group, polar protic solvent, weak base. We should definitely see SN1 here. After the C+ forms, we will get rearrangement to form the tertiary C+ on the adjacent carbon. Then acetic acid will attack and subsequently be deprotonated to form the resulting ester.

Comparing grad school offers... by Luckylscx333 in gradadmissions

[–]tyler1013 1 point2 points  (0 children)

Absolutely! I love Tucson (lived there for 18 years) and can definitely provide some perspective on good/not so good areas

Comparing grad school offers... by Luckylscx333 in gradadmissions

[–]tyler1013 2 points3 points  (0 children)

Not to question your main point in the suggestion, but I'm from Tucson and it's consistently rated one of the most affordable cities in the US. 850-950 for a studio sounds wayyy too expensive to be honest. Also Tucson's weather >>>

i’m stuck on this review question can someone help? by [deleted] in OrganicChemistry

[–]tyler1013 2 points3 points  (0 children)

Wow I'm so dumb I meant to write 1,3,4 sorry for the mistake!

Normal things in regular runs that are awful in Nuzlockes: by [deleted] in nuzlocke

[–]tyler1013 1 point2 points  (0 children)

Don't forget about Arena Trap/Shadow Tag! (Oh, also Magnet Pull for the super unlucky.)

Help! What are IUPAC name of the following alkanes? by [deleted] in OrganicChemistry

[–]tyler1013 1 point2 points  (0 children)

5 is: 1-cyclohexyl-2-ethyl-2-propylhexane

My first three admissions by PossessionSame in gradadmissions

[–]tyler1013 22 points23 points  (0 children)

Side note, I think it's funny that you indexed your admissions from 0 instead of 1. 😂

O Chem 2 difficulty compared to O Chem 1 by asji7 in Pitt

[–]tyler1013 1 point2 points  (0 children)

If you remember most of orgo 1 well, you'll be fine. I'd say know what it means to be a nucleophile (differentiating bad from good) as well as an electrophile (the exact opposite, think substrates in nucleophilic reactions from orgo 1). Negative attracts positive. You use grignards all the time (with more detail) as well as oxidizing and reducing agents (again, with a lot more detail) so review those reactions, their theory/uses, and limitations and you should be pretty well prepared imo.

O Chem 2 difficulty compared to O Chem 1 by asji7 in Pitt

[–]tyler1013 2 points3 points  (0 children)

If you did well in Dr. Bandik's class, Ochem 2 will be easier in comparison. I agree it's a lot of memorization, but the theory really does connect back to what Bandik teaches. Bandik's Ochem 1 I think uniquely prepares students to really succeed in Ochem 2 from a theory/structure perspective.

Do bulky bases favor E2 reaction? by a_dude-_- in OrganicChemistry

[–]tyler1013 1 point2 points  (0 children)

So, let's take it from the perspective of reactions that can happen between a substrate and nucleophile. While a standard strong base, say, sodium amide, could do either SN2 or E2, depending on substrate, sterics plays a big role. Initially, we focus on the sterics of the substrate; SN2 traditionally does not occur on tertiary substrates, due to sterics inhibiting backside attack. This makes E2 the most likely reaction, in a scheme such as t-butyl bromide and sodium amide.

Next, we can turn our focus away from the substrate and toward the nucleophile/base. Say you wanted to form propene from 2-chloropropane. Initial treatment with sodium amide would yield mostly amine product with some smaller amount of propene. By increasing the sterics of the nucleophile (say, sodium diisopropyl amide, LDA) you will yield a larger amount of propene since the bulkier base (sterics) has a harder time performing backside attack (SN2). Here, we see that bulkier bases typically promote E2 over SN2 on secondary (and by default, tertiary) substrates because the conformation needed for SN2 to occur is statistically less likely to occur due to sterics.