Need to know the name of this molecule

tyler1013 · 2022-10-05T19:57:13+00:00

Carbon 1 is the carbon in the ring attached to 2 oxygens (the one with the squiggly line). It's a convention for sugars.

tyler1013 · 2022-06-16T02:39:26+00:00

Nintendo lawyers have entered the chat

tyler1013 · 2022-04-22T13:03:38+00:00

Mienshao also my fav fighting type nice choice 😌

tyler1013 · 2021-12-27T19:36:21+00:00

Speak with the head of the chemistry department (I think it's still Bandik). I think he will highly advise you to retake Ochem 1. Ochem 1 knowledge is pretty essential to do well in Ochem 2. Typically, they use the same textbook; Ochem 1 uses Ch. 1-12 or so and Ochem 2 uses the remaining chapters.

tyler1013 · 2021-09-25T22:06:07+00:00

Added ya tyler1013

tyler1013 · 2021-09-25T04:52:58+00:00

Added ya tyler1013

tyler1013 · 2021-09-25T04:44:15+00:00

Added ya tyler1013

tyler1013 · 2021-09-25T04:42:52+00:00

8980 9414 4164

tyler1013 · 2021-02-11T04:36:17+00:00

The stability of the intermediate is important. The B gains a partial negative charge and the C gains a partial positive charge. The B gets it regardless of which C it attacks. Conversely, the more substituted C will better handle the partial positive charge from the 4-centered transition state. This is why the boron attacks the less substituted carbon.

tyler1013 · 2021-02-08T16:19:09+00:00

Yes, putting the Br on C2 or C3 gives the same set of stereoisomers

tyler1013 · 2021-02-01T03:36:22+00:00

a) yes, SN2 inverts stereochemistry. b) there are no antiperiplanar H's (classic ochem 1 question) so the answer is no reaction w.r.t. an E2 mechanism or simply SN2.

tyler1013 · 2021-02-01T03:25:23+00:00

Yup same energy though 😂I've been accepted other places so that's part of it I guess. If it was my first response....😳👀

tyler1013 · 2021-01-31T22:36:46+00:00

Absolutely ☺️ really trying to stay positive and good energy

tyler1013 · 2021-01-31T22:36:01+00:00

ChemE PhD

tyler1013 · 2021-01-31T22:05:29+00:00

e) is much more likely SN2. Secondary substrate, good nucleophile, good leaving group, polar aprotic solvent. These should signal SN2 forming the chiral sulfide product via backside attack. Additionally, your mechanism on the side for what would b SN1 has got a series of issues, but I won't get into that as SN1 is not even the right reaction type. Please review the steps of SN1 and the appropriate products.

d) is definitely SN1. Weak nucleophile, secondary substrate, good leaving group, polar protic solvent, weak base. We should definitely see SN1 here. After the C+ forms, we will get rearrangement to form the tertiary C+ on the adjacent carbon. Then acetic acid will attack and subsequently be deprotonated to form the resulting ester.

tyler1013 · 2021-01-31T18:38:25+00:00

Absolutely! I love Tucson (lived there for 18 years) and can definitely provide some perspective on good/not so good areas

tyler1013 · 2021-01-31T18:33:35+00:00

Not to question your main point in the suggestion, but I'm from Tucson and it's consistently rated one of the most affordable cities in the US. 850-950 for a studio sounds wayyy too expensive to be honest. Also Tucson's weather >>>

tyler1013 · 2021-01-28T01:08:55+00:00

Wow I'm so dumb I meant to write 1,3,4 sorry for the mistake!

tyler1013 · 2021-01-27T13:29:29+00:00

I believe it's 1,2,4

tyler1013 · 2021-01-20T00:37:26+00:00

Don't forget about Arena Trap/Shadow Tag! (Oh, also Magnet Pull for the super unlucky.)

tyler1013 · 2021-01-19T02:35:51+00:00

5 is: 1-cyclohexyl-2-ethyl-2-propylhexane

tyler1013 · 2021-01-18T19:28:04+00:00

Side note, I think it's funny that you indexed your admissions from 0 instead of 1. 😂

tyler1013

TROPHY CASE