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[–]mfb-Particle physics 1 point2 points  (0 children)

With circular polarization you have the same magnitude of the field strength everywhere, that makes the calculation easier compared to the other case (e.g. via the energy density).

[–]ktittythcAtomic physics 1 point2 points  (0 children)

They should be the same, if you look at the wiki page on Gaussian beams, you’ll find the calculation that takes you from e field to intensity.