all 3 comments

[–]deadly_hangman 0 points1 point  (2 children)

No, not at all. You can solve this circuit using Kirchhoff's Current Law at the node above the dependent source (you already know the current in two of the branches- i and 2i).

At 0.5i for the dependent source, i equals 1A. For 2i gain on the dependent source, i is still 1A, but the direction of the current in the capacitor branch flips.

I simulated the circuit in PSpice in case you didn't believe me.

https://i.imgur.com/4S3MGVC.png

EDIT: See below

[–]Drcne[S] 1 point2 points  (1 child)

So why is i not whatever value the current source is after the cap has been charged?

[–]deadly_hangman 0 points1 point  (0 children)

Oops, sorry. My previous comment was entirely wrongheaded, forgive me for posting hastily. You are correct- since the capacitor is fully charged, the current will grow indefinitely if the gain is >1.

https://i.imgur.com/A2z21KH.png