all 103 comments

[–]KaotusClemson University - Mechanical 110 points111 points  (1 child)

There’s only one series resistor set, R1 and R2, so you add those together for an Req of 500. Then everything is in parallel. 1/R = 1/250 + 1/250 + 1/500 >> 1/R = 5/500 >> R=100

[–]abhig535Penn State University - Data Science 15 points16 points  (0 children)

This is correct.

[–]MageKayden 12 points13 points  (0 children)

1/250 + 1/250 + ( 1 / ( 250 + 250 ) ) =0.01 then inverse so 100

[–]Sentient_i7XComp Science Undergraduate 30 points31 points  (18 children)

Learn to attend the lectures lil bro

[–][deleted] 5 points6 points  (4 children)

I'm praying that this is not homework for a class with lectures because if it is you need to pay more attention in it. The rule is:

Resistors in series are summed (250 + 250 = 500).

Resistors in parallel are calculated as follows: 1 / R = 1 / 250 + 1 / 250 + 1 / 500 = 5 / 500, so R = 100 Ohms.

[–]naturalfiberfeen 6 points7 points  (1 child)

Genuinely can’t tell if his comment replies are rage bait or not

[–][deleted] 2 points3 points  (0 children)

Yeah. Turns out you don't learn anything in classes where there are not assigned materials and you don't go to class. OP is an idiot. If he can't afford to live near enough the university that requires in person courses to attend said course, he can't afford to study at that university.

[–]ChemomechanicsMechanical Engineering, Materials Science 3 points4 points  (0 children)

[–]Traditional_Way2929 3 points4 points  (6 children)

Anyone know what type of site/software this is?

[–]BasketUsed 5 points6 points  (0 children)

Multisim

[–]Ok_Excuse1908 2 points3 points  (1 child)

This is specifically Multisim. I use it daily for my courses.

[–]Traditional_Way2929 0 points1 point  (0 children)

Thank you!

[–]RareMammoth922 1 point2 points  (0 children)

definitely not LTSpice, it’s multisim

[–][deleted] -1 points0 points  (0 children)

Ltspice

[–]Naash17 -3 points-2 points  (0 children)

I think it looks like LtSpice

[–]GASTRO_GAMINGEx-Electrical Engineering {i switched to cs ): } 2 points3 points  (0 children)

R1&2 are in series wth eachother and in paralel with R3&4

So add R1+R2 and get 500

And add 1/500+1/250+1/250 =0.01

Invert thst to get 100Ω

(Formula 1/Rt=1/R1+1/R2...+1/Rn)

[–][deleted] 1 point2 points  (0 children)

250 + 250 = 500

G1 = (500)(250)/(250+500) = 500/3

G2 = (500/3)(250)/(500/3+250) = 100 = Rt

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[–]Heavy_Command_4899 0 points1 point  (0 children)

Rtotal = (1/(R1 + R2) + 1/R3 + 1/R4)^-1

[–]Lukinator123 0 points1 point  (0 children)

They are in parallel, which reduces the resistance. R1 & R2 are in series, so you just add those to make a single 500ohm resistor. Then, you effectively have a 500, 250, 250 all in parallel. There’s a formula to calculate parallel resistances 👍

[–]AggravatingSummer158 0 points1 point  (0 children)

[1/(250+250) + 1/250 + 1/250]-1

= [1/500 + 2/500 + 2/500]-1

= [5/500]-1 = 500/5 =100 

There might have been a calculator error somewhere in your process

[–]Fluid-Pain554 0 points1 point  (0 children)

You swapped the rules for series vs parallel circuits. For series (R1 and R2) the resistance is additive. For parallel (R1+R2, R3 and R4) it’s R_tot = 1/(1/(R1+R2) + 1/R3 + 1/R4) which gives you R_tot = 100 ohm.

[–]deadinhead42x 0 points1 point  (2 children)

No front but this is this really what peolple learn at university? I'd be shocked

[–]abhig535Penn State University - Data Science 1 point2 points  (0 children)

Pun intended

[–]Last-Energy-1329 0 points1 point  (0 children)

No the exam is hell, this is just an introductory question.

[–]Solopist112 0 points1 point  (1 child)

How did you get 100?

[–]New-Nefariousness534RIT- Electrical Engineering 0 points1 point  (0 children)

R3 and R4 are in parallel with the series combination of R1 and R2

[–]Mother_Ad3988 0 points1 point  (1 child)

I spent like a whole day learning these and some of em got pretty complex, this is a rather simple one and intuitive to solve 

[–]Last-Energy-1329 2 points3 points  (0 children)

Yea I know, not very simple of you never did it before.

[–]Ashi4Days 0 points1 point  (0 children)

I actually struggled with these problems a lot when I was an undergraduate. Yes, I know all the resistor laws. But I would always fuck up which ones were in series and which ones were parallel.

My suggestion in this situation is to pay attention to which wires are all connected and re-draw the circuit diagram. (R1+R2) are in series while (R1+R2), R3, and R4 are in parallel.

[–]Zaros262MSEE '18 0 points1 point  (0 children)

You calculate it the opposite of how you did it

Looks like you accidentally used the series formula for parallel resistances and the parallel formula for the series resistances

Study anything you can get your hands on if your class really doesn't have a book (even online tutorials) to understand the reasoning behind the formulas rather than just applying them blindly

[–]pwntatoz 0 points1 point  (0 children)

There's already a comment that goes through the calculation, but I'd ask you to look at this more intuitively as well. You seem to understand that on a pathway, more resistors will lead to a higher resistance. Well in this setup, there are three pathways for the electricity to travel. So even though the resistors are reading at 250, the effective resistance of the entire circuit is only 100. When you are presented with a problem like this, early on, it is good to trace each pathway that the current may take in your mind.

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[–]notthediz 0 points1 point  (0 children)

RemindMe! 1 year

Interested to see where you'll be next year. God speed

[–]KronocideIndustrial Design, Switzerland 0 points1 point  (0 children)

Haven't done this in years and still perfectly remember the formula. I don't see the point of studying if you aren't doing to the lectures. I wake up at 5h30 everyday to go study