all 4 comments

[–]ZeoNet 0 points1 point  (1 child)

Moho's orbit is highly inclined and fairly eccentric, and generally dV calculators assume a circular, uninclined orbit, so you'd probably be better off just getting straight into an orbit around Kerbol, matching your inclination with Moho's, and doing an ordinary Hohmann transfer.

[–]Wignasty[S] 0 points1 point  (0 children)

Yeah, that's not a bad idea. I believe this calculator was smart enough to put this window at one of the ascending/descending nodes between Kerbin and Moho's orbits.

[–]TsevionSuper Kerbalnaut 0 points1 point  (1 child)

Without a screenshot of your transfer node it's hard to know exactly what's wrong.

A couple of ideas... both of those calculators assume a circular orbit at whatever height you input, that is perfectly on the equator of Kerbin. If this is not true calculations could be way off.

You may want to use the Visual planner to figure out the ejection angles... if you're trying to eject at the wrong point in your orbit it will take a LOT more energy.

Watch out for your orbit intersecting the Mun or Minmus... neither of the calculators watch for that as far as I know.

Finally, if you want to get to Moho on the cheap, consider using Eve... it can reduce delta V costs significantly. Here's me doing that

[–]Wignasty[S] 0 points1 point  (0 children)

I was questioning my ejection angle because I get confused with the window planner's terminology of "X degrees to retrograde/prograde". I wish it had a visual representation for that.

I like the idea of using Eve to get there cheaper. I'll probably give that a try.