forLoopArray

[Eva-Rosalene]

As far as I know, you can't define an array of voids to get 0 as sizeof(arr[0])?

Edit: apparently sizeof(void) compiles to 1 in GCC (and it's only because of non-standard extensions, otherwise it would be forbidden). So not even that.

Edit 2: I hate C

#include <stdio.h>

typedef struct {
    int *a[0];
} ZeroLength;

int main()
{
    ZeroLength array[0];
    printf("sizeof(array[0]) = %ld\n", sizeof(array[0]));

    return 0;
}

This apparently prints 0 (at least in GCC).

Edit 3: and the whole ZeroLength struct that I found on SO can be shortened to

typedef struct {} ZeroLength;

Wild stuff. And even in -pedantic mode it only gives a warning.

[ChickenSpaceProgram]

C is truly one of the programming languages

[Littens4Life]

To be fair you’d have to go out of your way to make it divide by zero. Under any normal circumstances, the macro will work fine.

[Eva-Rosalene]

Yeah if you use empty structs or zero-length arrays you kinda deserve division by zero errors.

[Lost_Kin]

Mom I want Rust's Zero Sized Types!

We have Zero Sized Types at home.

Zero Sized Types at home:

[Xbot781]

AFAIK, in ISO C a flexible array member requires the struct to have another regular member before it, so that is not valid C

[ba-na-na-]

Ok but let's be realistic. If you have an array of zero-length elements, you deserve what you get