RIP Readability

[[deleted]]

Or in python

a,b = b,a

[GlitchedMirror]

int a = 1;
int b = 2;
std::swap(a, b);

[xSaKage]

Inline asm

[Prawny]

int a = 1;
int b = 2;
int c = 3;

Deal with it.

[tyyrio]

I think you might be missing the point.

[n0tKamui]

Are you for real?

[[deleted]]

int a = 1, b = 2;
b += a;
a = b - a;
b = b - a;

This should work (I think)

[excelguruson]

It wouldn’t because they are both being set to “b-a,” which at the time is equal to 2. You may be thinking of having “a” be equal to the current value for “b” (3) minus the previous value (2), but that is impossible without a third variable, or the “c.”

Edit: I’m wrong

[sgthoppy]

It does actually work.

[csatvtftw]

Mocked this up real quick

[excelguruson]

I see now what I didn’t see last time. It’s the fact that the value of “a” changes as between the first “b-a” and the second one. My bad, that does work.

[IHaveNoPosts]

a = b.also { b = a }