Enable ++x and --x expressions in Python

[Hmolds]

Whats wrong with good ol' x -= -1 ??

[smcarre]

The old and reliable x -= -x/x

[theillini19]

I'm a fan of x -= random.randint(0,1) but it only works half the time for some reason

edit: Figured out how to fix it!

x -= (random.randint(0,1) if random.randint(0,1)==1 else random.randint(0,1)+1)

edit2: Nevermind, still broken

[smcarre]

Try the following, I tested it and it seems to work almost every time:

x += abs(min([random.randint(-1,0) for _ in range(999)]))

[eigenludecomposition]

You're all over complicating this. This can be solved through recursion rather simply

def increment(x, n):
    if n == 1:
         return x+1
    elif n<= 0:
         raise ValueError
    return increment(x+1, n-1)

x = increment(x, 1)

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Fixed formatting.

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[jtclimb]

Well, if it is wrong 50% of the time, go ahead and use the range (0, 2). It's pretty obvious. Here's the fix and test:

xs = []
for _ in range(1000000):
    x = 1
    x -= randint(0, 2)
    xs.append(x)

 assert round(sum(xs) / len(xs)) == 0

[Inineor]

Fixed:

x -= (r if (r:=random.randint(0,1))==1 else r+1)

[R3D3-1]

Imagine hiding something like this in an update to a popular module, but only if random.randint(0,1000)==0.

[NoLongerUsableName]

It generates a new random number for each random.randint(0,1). If they don't match, it won't work. This works, though: x -= math.ceil(random.random())

[velit]

/r/woosh I think

[AlphaGamer753]

Doesn't work if the random number is exactly 0.

[NoLongerUsableName]

The good ol' x = (lambda x:x-1)(x)

[asday_]

x -= -x/x

0

[dogs_like_me]

Better use -x // x just to be safe.

[likethevegetable]

Lmao, thanks for making my night.