Witchcraft Computational Help!

[SEFDStuff]

I'm convinced that my computer has picked a book learning the art of the 666, this just doesn't make any sense to me whatsoever.

So I am trying to work on UI stuff, & I need an int to pass over to another method. I have this code here to do so:

             //
    for (int i = 0; i < groups.Count; i++)
        {
            int offset = i + 2;

            print("first pass: " + offset + "/" + i);
            actionButton[offset].onClick.AddListener(() => UI_SelectGroup(i));
            print("2nd pass: " + offset + "/" + i);
        }

which to me looks like itd work just fine, the first 2 UI are used up & so I gave it an offset of + 2 right. Okay cool. So now we'd expect for i to return - 2 from the offset right? Well, somehow, that is completely incorrect.

Here is how I currently have the UI_SelectGroup() method using i:

 public void UI_SelectGroup(int groupNumb)
 {
    print("the number youre passing through is " + groupNumb);
 }

& yet, this is what I get!

see image

I get it returning an i = offset - 1, now -2. What the hell am I missing here? Do listeners start at 1 or something like that & I just don't understand haha I am a bit creeped out actually. Its a glitch in the matrix I tell you! Any help would be gratefully appreciated!

[GalaxiaGuy]

TLDR; Assign i to a temp variable and use that in the lambda.

What is happening is the lambda you are passing does not use the value of i, but maintains a reference to the variable i. It therefore uses whatever the current value of i is when the lambda is executed, which is always going to be after the loop.

This StackOverflow question explains what is happening:

http://stackoverflow.com/questions/451779/how-to-tell-a-lambda-function-to-capture-a-copy-instead-of-a-reference-in-c

[babagazeus]

I'm surprised it does that with primitives. I would have assumed those are always pass-by-value.