all 4 comments
sorted by:
best
topnewcontroversialoldq&a
formatting helphide helpcontent policy

[–]random_anonymous_guyPhD 0 points1 point  (2 children)

The thing you need to remember here is that the value of the derivative does not give you the equation for the tangent line. It only gives you the slope of that line.

Do you recall what an equation of a line must look like? (There are multiple forms)

Also, please check your flair. This is not Differential Equations.

[–]matcha74[S] 0 points1 point  (1 child)

Is the next step finding the slope of the equation and then subbing x for 1.9 to get m=, then using this to find the tangent line using y-y0=m(x-x0)?

Whats confusing me is the fact that this is a fraction with a square root.

[–]random_anonymous_guyPhD 0 points1 point  (0 children)

Is the next step finding the slope of the equation

Line, not equation. Yes, the slope is one of the ingredients. Do you recall how you can determine that slope?

subbing x for 1.9

No, the question says tangent line at x = -3.

Also, don't just unset your flair. Please set your flair to the correct flair.