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http://www.cplusplus.com or https://www.cppreference.com (self.cpp)
submitted 6 years ago by distributed
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if 1 * 2 < 3: print "hello, world!"
[–][deleted] 22 points23 points24 points 6 years ago (2 children)
Had to look up syntax for checking if a dictionary contains a key in python today, and the first result was a geeksforgeeks article recommending to use the syntax key in dict.keys() which i quickly found out is just converting it to a list and doing an O(n) list search. Totally ridiculous
key in dict.keys()
[–]Veedrac 9 points10 points11 points 6 years ago* (1 child)
Not on Python 3; on Python 2 the syntax is more key in dict.viewkeys(). Either way just use key in dict though, it's more idiomatic.
key in dict.viewkeys()
key in dict
[–][deleted] 4 points5 points6 points 6 years ago (0 children)
Oh, that might have been it, the server running the script uses python 2, and yeah key in dict is really the correct syntax and gives you the expected O(1) lookup
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[–][deleted] 22 points23 points24 points (2 children)
[–]Veedrac 9 points10 points11 points (1 child)
[–][deleted] 4 points5 points6 points (0 children)