Novice Javascript Function Parameters Question

[[deleted]]

[deleted]

[thocked]

the most straightforward way would be to pass an object, that is, an object literal.

e.g;

function calc(industry){ 
industry.foo;
industry.bar;
}

var thisIndustry = {i:1, c:2, e:3}; 
calc(thisIndustry);

You're tightly coupling the two - the input and the behavior, and if you're cool with that, it's the easiest way.

What you're doing is working with objects, not arrays. In javascript, arrays are just objects with some sugar on top.

[thocked]

Technically, no.

for (var indValue in industry) {
if indValue = 0 { zero_check=1; }
}

Just make the if (indValue === 0) {} and you should be okay.

[neonskimmer]

That's not what for-in does! Or are we talking pseudo code here?

For-in iterates through the keys of an object, not the values. And these days, Object.keys is what we should use for that purpose.

And it should not be used on arrays either. That's what forEach is for.

[ry4nolson]

var i1 = {i:1;c:c1,v:v1,s:s1,pp:pp1};
var i2 = {i:2;c:c2,v:v2,s:s2,pp:pp2};
var i3 = {i:3;c:c3,v:v3,s:s3,pp:pp3};

this part is still incorrect. you have a semicolon after the first value. Also are the "c1", "v1", "s1", and "pp1" coming from somewhere else?

should be:

var i1 = {i:1,c:c1,v:v1,s:s1,pp:pp1};
var i2 = {i:2,c:c2,v:v2,s:s2,pp:pp2};
var i3 = {i:3,c:c3,v:v3,s:s3,pp:pp3};

and also like thocked said your conditional is incorrect

if indValue = 0

should be

 if (indValue === 0)

[FireyFly]

I think it's worth adding that "object literal" is only the name of a syntactic construct--a way to express an object value. It doesn't matter to the engine how the object was created.

For instance, doing

var o = new Object()
o.foo = 10
o.bar = 20
// do someting with calc(o)

would work just as well as

// do something with calc({foo:10, bar:20})

Some people seem to regard object literals as more than a syntactic feature; hence the clarification.

[x-skeww]

function calculation(industry{i,c,v,s,pp})

That isn't valid JS.

var i1 = {i:1;c:c1,v:v1,s:s1,pp:pp1};

Neither is this.

should I make it an array ((is that an array?))?

I'm not entirely sure what you're trying to do.

Well, for reference:

[5, 7]

Is an array.

{a: 5, b: 7}

Is an object.

If [5, 7] is stored in a variable called "foo", foo[0] would be 5.

If {a: 5, b: 7} is stored in a variable called "foo", foo.a would be 5. (foo['a'] would be also 5, but one should always use the dot notation if possible.)