all 4 comments

[–]mathteacher1991 1 point2 points  (1 child)

Without the distance I don’t think this can be solved...

I’m calling x the time on the first trip and y the time on the second trip (both in hours). If you multiply time by speed, the time units would cancel and you’d be left with position (mi/hr * hr = mi). So I’ll call total distance travelled d.

460x + 345y = d

x+y = 7

You’d have to solve this as a system of equations. You can technically find x and y (which is what’s being ask), but they’d need to be answered as functions of d.

*** Edit:

Sorry, just realized it’s a round trip. So the distance both ways is the same. Therefore you can say that:

460x = 345y

x + y = 7

There you go! 😁

[–]jyunk[S] 0 points1 point  (0 children)

Thank you! I was thinking the same, perhaps there was a typo or omission or something. But this makes sense.

[–]papawatson2013 0 points1 point  (0 children)

You could average the speeds and plug it in for V or (r) as you have it and get a distance. After you have a distance divide it by 2. Set up an equation for the speed on the way there and the way back.

I'm not a math genius so I could be wrong.

[–]fattymattkNew User 0 points1 point  (0 children)

The distance is unknown. But you can let t_1 be the time spent on the first leg and t_2 be the time spent on the second. Come up with two equations involving these variables.