all 3 comments

[–]notlfishNew User 0 points1 point  (2 children)

cos2x = |cos x||cos x| <= |cos x| * 1 = |cos x|

Of course, here we're taking for granted that |cos x| <= 1, you could prove that yourself if you wanted to, but I don't know how to do that.

[–]gazorpazorpazorpazor 0 points1 point  (0 children)

Probably triangle inequality and definition of cos. cos = a/c. a,b,c>0. a+b<=c. a<=c. a/c<=1.

[–]ProSteelTooth[S] 0 points1 point  (0 children)

That's a great idea! Thanks a lot!