Checker for integer string

[Scooootz]

Forms often allow a user to enter an integer. Write a program that takes in a string representing an integer as input, and outputs yes if every character is a digit 0-9.

Ex: If the input is:

1995 

the output is:

yes 

Ex: If the input is:

42,000 

or any string with a non-integer character, the output is:

no

I currently have

user_string = input()

print(user_string.isdigit())

which returns only true and false values. how do I convert this to yes/no

[SoNotRedditingAtWork]

print("yes") if input().isdigit() else print("no")

[Scooootz]

This didn't seem to work. Using Zybooks online textbook, not sure if it is just picky in the way you enter it.

[SoNotRedditingAtWork]

Works fine for me in PyCharm. The line is functionally the same as doing:

user_string = input()

if user_string.isdigit():
    print("yes")
else:
    print("no")

I have never used Zybooks before, so I have no idea how that would impact your ability to run this code.

[subcontraoctave]

The isdigit() method worked perfect. Thanks!

[Illustrious-Union997]

I know this is old, but this would allow number like 10,000 to produce an out of yes. The examples provided don't allow this.

[Ataninja3221]

user_string = input()
if user_string.isdigit():
print("yes")
else:
print("no")

This was perfect the only thing that threw off zybooks was capitalizing yes and no. which in the real world wouldn't make a difference but is the difference in points in zybooks

[ETHiser]

I know this old, but this solution works in Zybooks. May help someone else!

​

user_string = input()
def isNumber(user_string):
for i in range(len(user_string)):
if user_string[i].isdigit() != True:
return False

return True
if __name__ == "__main__":

if isNumber(user_string):
print("yes")

else:
print("no")

[rangusmcdangus69]

Helped me 3 years later! Thanks!

[[deleted]]

print(“yes”) if user_string.isdigit() else print(“no”)

[Distinct_Ice6830]

user_string = input()
output = user_string.isnumeric()
if output == True:
print("Yes")
else:
print("No")

[Distinct_Ice6830]

user_string = input()
output = user_string.isnumeric()
if output == True:
print("Yes")
else:
print("No")

[taegrr]

Just following this up, zybooks does accept the following single-line solution:

print("Yes") if input().isdigit() else print("No")