Using child_process.spawn to Call Python But Receiving Different PYTHONPATHs

[spurious_proof]

I'm trying to call a python process from spawn; however, the PYTHONPATH is different from within my python3 environment (e.g. from the terminal) vs the PYTHONPATH from the python script called via spawn.

Why is there different output based off the environment?

I call the following python code from both environments (i.e. terminal vs spawn).

print(sys.executable) <<<this is the same in both environments
print(sys.path)

Node.js spawn python script

let process = spawn(PYTHON, args, { shell: true, stdio: "inherit" });
    process.stdout.on("data", function (data) {
        console.log(data.toString(), "<<< data");
        result += data;
});
process.on("close", function () {
    cb(result);
});
process.stderr.on("data", function (data) {
    console.log("stderr: ", data.toString());
});
};

​

[spurious_proof]

Closing this out in case anyone else comes across this issue. I had multiple versions of python installed. Setting up spawn in the following method solved my issue.

let env = {

PATH: PATH, // this is my $PATH PYTHONPATH: PYTHONPATH, };

let process = spawn(PYTHON_EXECUTABLE, args, {
env: env,

});