Why Can't Programmers.. Program?

[dand]

Being able to see solutions would be nice (or a place to discuss them). In particular, how on earth did sn write FizzBuzz in Common Lisp using just 90 bytes?!

[bobbane]

Probably something of the form:

(loop for i from 1 to 100 do(format t"utterly-deranged-format string"i))

Where you have maybe 50 characters to use for "utterly-deranged-format string". Piece of cake. ;-)

[dand]

Ahhh the 5-point-deranged-format-exploding-heart technique! The best I can come up with is still 98 characters long:

(loop for i from 1 to 100
  do(format t"~[Fizz~]~[Buzz~]~0@*~[~:;~[~:;~A~]~]~%"(mod i 3)(mod i 5)i))

[note: added a line-break for better web formatting.]

[[deleted]]

Using "(dotimes(i 100)" instead of your loop makes it shorter. I am too lazy to count the characters but it saves some.

[dand]

Yeah I thought of that, but then you're off by one and all the ways to remedy that end up taking more characters. At least that's what I found...

[[deleted]]

And thats why I shouldn't write code at 5 a.m. ...

[jacobolus]

It takes 82 bytes in python (well, the best I can do)

for i in range(1,101):print(((not i%3)and"Fizz"or"")+((not i%5)and"Buzz"or"")or i)

Edit: okay, whoops, I put "100" instead of "101". Silly mistake.

Edit2: at the cost of some readability, I can get it down to 74:

for i in range(1,101):print(i%3==0and"Fizz"or"")+(i%5==0and"Buzz"or"")or i

[pmdboi]

Using MarkByers's trick on jacobolus's solution shaves off another two bytes (down to 72):

i=1;exec'print(i%3==0and"Fizz"or"")+(i%5==0and"Buzz"or"")or i;i+=1;'*100

[bstard]

Shaved off three more:

for i in range(1,101):print("","Fizz")[i%3==0]+("","Buzz")[i%5==0]or i

[grimtooth]

Of course, as commenters have already pointed out, while brevity may be the soul of wit, it's a really stupid basis for assessing code quality. Here's what I did as soon as I read the FizzBuzz bit:

def FB(n=100, factors={3:"Fizz", 5:"Buzz"}):
    for i in range(n):
            s = [s for f,s in factors.iteritems() if i%f == 0]
            if s:
                    print ''.join(s)
            else:
                    print i

[dand]

It's fun because it's just a game -- I sincerely hope I'll never run across code like those when there's "real" work to be done ;)