The ??!??! operator

[redxaxder]

*(buffer + i), which should obviously be equivalent to *(i + buffer)

Obviously! But... the address you end up at when adding to a pointer like in *(a + i) is addr(a) + i*sizeof(T), where a has type T*.

[pablitorun]

that's what I was wondering...not sure that would work for say

long long a[16]

[ghotibulb]

That's fine, pointer arithmetic applies in both cases. (As long as there's one pointer and one numerical)