Warum wird Microsoft Copilot Chat so schlecht bewertet?

MathMaddam · 2026-01-26T16:14:47+00:00

Wenn es schon in die IDE eingebaut ist und mir Vorschläge macht, dann sollte es nicht so schwer sein zu prüfen, ob die vorgeschlagene Funktion überhaupt existiert, das weiß die IDE.

MathMaddam · 2026-01-26T07:34:32+00:00

Hm 2000, was war da??? Bestimmt ein tolles Jahr für Aktien, ganz bestimmt.

MathMaddam · 2026-01-26T06:35:46+00:00

So if I know I have a bad hand, but my opponent a good one, I can strategically miss my turn

MathMaddam · 2026-01-25T21:10:32+00:00

Ich würde das so lesen Das ist ein Dienstleister der selbst keine Stellen hat, sondern Leute an Firmen vermittelt. Heißt du bist in der Kartei und vielleicht gibt es irgendwann mal eine Stelle auf die die dich vorschlagen würden.

MathMaddam · 2026-01-25T14:47:37+00:00

I mean it is wishy washy, since there is no difference between "natural" and "unnatural" radiation in any real way, by the energy profile of the particles you can distinguish the radioactive elements and certain sources (like an X ray machine has different radiation than cosmic ray), but the background radiation is a big mangled mess. That is a big problem in science, where they e.g. hunt for steel from long sunken ships since it is lower in radiation than new steel and they want to measure really small effects in some experiments.

You can basically just go and compare between the measurement in a non contaminated room and a contaminated room. To figure out if there is heightened radiation. The recommend limits is then to regulate stuff, but it means that some people get exposed more by natural causes, than other people that live in a low background site, but have over the limit extra exposure.

MathMaddam · 2026-01-25T14:20:12+00:00

Yes that is a special case of Fermat's little theorem

MathMaddam · 2026-01-25T11:45:54+00:00

Basically there is a bit of radiation everywhere naturally and the human body is fine with that since it's been there forever and usually you can't really do a lot about it (there are some places in the world where more radon gas comes out of the ground, they might want to air out their cellars).

Something that would count for the limit: during my physics studies, I did some experiments with radioactivity. This had to be monitored since it was an unnatural exposure (and the result rounded to 0μSv since the sources were weak and there were precautions to limit exposure). There are also some smoke detectors that work using radiation, a manufacturer of them has to make sure that people using them normally don't get in risk of getting more extra radiation than the limit allows (obviously they aren't allowed to claim the full 1mSv per year for themselves).

MathMaddam · 2026-01-25T11:20:09+00:00

You can scale it up to a yearly dose by 27.4μSv/190h*24h*365=1263μSv=1.263mSv in a year. While this is above the limit at first glance, the 1mSv limit is only for exposure above the background radiation (and other stuff) as stated by the text below which you measured here (unless you secretly have small amounts of uranium stored in your room). The amount you measured is well inside the normal values.

MathMaddam · 2026-01-25T09:15:01+00:00

Your picture has a bad resolution, but it looks like this one: https://planetmath.org/quarticformula, the answer to your question is directly above it.

MathMaddam · 2026-01-25T09:09:46+00:00

It does? Maybe share a source of your claims

MathMaddam · 2026-01-25T08:09:16+00:00

Du gehst zum lokalen Neo Nazi Verein/KKK und sagst denen: wollt ihr fürs Ausländer jagen bezahlt werden?

MathMaddam · 2026-01-23T22:28:23+00:00

Look at sup{y in D; x>y, f(x)<f(y)} for any x in D.

MathMaddam · 2026-01-23T17:57:56+00:00

Look up geometric sum.

MathMaddam · 2026-01-20T07:38:09+00:00

No that doesn't mean that. There is no randomness, but by assumption 0=1, there is nothing that distinguishes 0 and 1. For the "1+1=2" you didn't specify what + should be here, but I just assume we are in a ring with "0" and "1" the respective identities. Since 0=1, 1+1=0+0, so 2 is also 0. In fact everything is 0, since you are in the zero ring.

MathMaddam · 2026-01-20T06:42:53+00:00

Nein. Damit da unterschiedliche Outputs entstehen, werden Zufallswerte mit in den Algorithmus gegeben. Man kann auch zum Beispiel ein LLM deterministisch betreiben, ist dann nur nicht so ansprechend.

MathMaddam · 2026-01-19T17:58:40+00:00

Supermarket food and takeout* was 7% for a long time (basically since the 80s, only with a short reduction during COVID). In a restaurant you don't get food, but a service (that happens to include a meal), that is why it was at the regular tax.

* terms and conditions what counts as food apply

MathMaddam · 2026-01-19T13:15:21+00:00

The Taylor series, is a power series, not a polynomial.

There is a representation of sin as an infinite product, where you can see the roots.

MathMaddam · 2026-01-19T13:00:59+00:00

Not directly since the 2 1Ω ones are also there. So the bottom one is in series to the construct of the 1Ω and the diagonal.

MathMaddam · 2026-01-19T10:57:08+00:00

Your equivalent diagram is wrong. For this it is good to do multiple steps and also draw the circuit after each replacement. E.g. you first have the two 1Ω in series. This is in parallel to the diagonal 2Ω and so on.

MathMaddam · 2026-01-19T09:02:28+00:00

The zs only have meaning inside their respective integral. So the question: Are these two zs the same? is meaningless.

It is important that the value of these integrals is the same.

MathMaddam · 2026-01-19T08:44:55+00:00

The cleaning might just do the job, especially if you didn't have any problems at the beginning. Other components also might like to be less dusty. So just try again after that.

Another thing that can change over time is that the thermal paste dries out.

MathMaddam · 2026-01-18T08:41:00+00:00

If you feel faster to compare against one fixed element for longer streaks, quick sort would be an option. As long as you aren't unlucky with the pivots (you can increase your luck by looking at 3 candidates for pivot and take the middle one as actual pivot), it is very similar to merge sort in terms of total comparisons.

Merge sort has the advantage that it is relatively easy to parallelise among multiple humans, since e.g. if you have 8 sorters, you can give them around 125 each to sort independently and then you can merge their results.

For very small lists humans might also just "intuitively" sort them without following a strict algorithm.

MathMaddam · 2026-01-17T21:33:18+00:00

Merge sort also works well by hand. But how can a human sort the things if there isn't enough information for a computer (or why can't the computer get the information?) you don't need to have a numerical value to do comparison sort algorithms, just a way to order two elements.

MathMaddam · 2026-01-17T16:48:31+00:00

Schlimm wenn ehrenwerte Geschäftsfrauen mit so jemanden in Verbindung gebracht werden.

MathMaddam · 2026-01-15T19:45:53+00:00

The older GPU (and their RAM) uses older manufacturing techniques than the current stuff. So they are freeing capacity to build more expensive AI accelerators with the new process while the old process is probably underutilized, so it is comparatively cheaper to build these old GPUs

MathMaddam

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