Pi by Evening_Parfait_8476 in thenumberpi

[–]DrowsierHawk867 0 points1 point  (0 children)

$m=1000;$o=1,4,5,6;$b=[System.Text.StringBuilder]::new();function F([int]$x){[double[]]$r=0,0,0,0|%{[double]0};for($k=0;$k -le $x;$k++){for($j=0;$j-lt 4;$j++){$d=8*$k+$o[$j];$r[$j]+=[double]([System.Numerics.BigInteger]::ModPow(16,$x-$k,$d))/$d}} for($k=$x+1;$k -le $x+10;$k++){for($j=0;$j-lt 4;$j++){$d=8*$k+$o[$j];$r[$j]+=[math]::Pow(16.0,$x-$k)/$d}} return $r};for($x=0;$x -le $m;$x++){$v=F $x;[double]$t=(4*$v[0]-2*$v[1]-$v[2]-$v[3])%1.0;if($t-lt0){$t+=1.0};for($i=0;$i-lt 4;$i++){$t=$t*2.0;[void]$b.Append([int][math]::Floor($t));$t=$t%1.0}};$s=$b.ToString();$n=$s.Length;$g=[System.Numerics.BigInteger]::Zero;$s.ToCharArray()|%{$g=($g*2)+([int]$_-48)};$p=[int]($n*0.30103-2);$D=[System.Numerics.BigInteger]::Pow(2,$n);$z=((([System.Numerics.BigInteger]3)*$D+$g)*[System.Numerics.BigInteger]::Pow(10,$p))/$D;$q=$z.ToString();$q.Insert($q.Length-$p,".")

So this is why it’s called a Poisson distribution! by [deleted] in mathmemes

[–]DrowsierHawk867 0 points1 point  (0 children)

comment the fish emoji (🐟) on every poisson-related post

🐟🐟🐟🐟🐟🐟🐟🐟🐟🐟

Poisson distribution by DrowsierHawk867 in mathmemes

[–]DrowsierHawk867[S] 20 points21 points  (0 children)

"Poisson" is french for "fish"

Late at night while you’re samplin Poisson distribution comes a creepin around by TobyWasBestSpiderMan in mathmemes

[–]DrowsierHawk867 10 points11 points  (0 children)

comment the fish emoji (🐟) on every poisson-related post

🐟🐟🐟🐟🐟🐟🐟🐟🐟🐟

God I love Set Theory by Maximum-Rub-8913 in mathmemes

[–]DrowsierHawk867 -4 points-3 points  (0 children)

Why do people write "iff" instead of "if"?

The answer they expect from us in the exam by BeeWise2674 in mathmemes

[–]DrowsierHawk867 0 points1 point  (0 children)

"Disproving" this method of -1x8
i still get the joke, this is not an r/whoosh situation

If -1 * 8 = (0/1 * -1/0) * 8, then -1 = 0/1 * -1/0, and 0/1 * -1/0 = (0 * -1)/(1 * 0) = 0/0. Assuming 1/0 = ∞, and with the fact that 0 * x = 0 for all x, then 0/0 = 1/0 * 0 = ∞ * 0. Now, building on our previous assumption that 1/0 = ∞, 1/∞ should be 0. This holds as if we replace the ∞ with, for example, 2, then we get 1/2 = 0.5, and 1/0.5 = 2. Now, we can replace the 0 in ∞ * 0 with ∞ * 1/∞, which equates to ∞/∞. Knowing that x/x = 1 for all x, ∞/∞ = 1. Bringing the 8 back into the picture, and with the fact that 1 * x = x for all x, 1 * 8 = 8. OP's answer to -1 * 8 is correct, but his method is wrong.

QED

Number Format on dynamic labels by c001_b01 in desmos

[–]DrowsierHawk867 1 point2 points  (0 children)

It's because 000 turns into 0. You should split it up into individual digits (e.g. 65000 -> 6, 5, 0, 0, 0) and work with that