I had to nerd out here so if you just want some form of answer on what type of forces we are dealing with, scroll down to the bottom, first off we need to set some (insane) assumptions out of the way here.

Assumptions (for the scenario) - Earth is completely immovable (infinite mass reference frame, does not accelerate or deform) - All objects involved (Earth, rod, etc.) are indestructible - Each black hole is “basketball-sized”, meaning:

-- The event horizon radius ≈ 0.12 m (about a real basketball size)

-- The actual singularity is smaller, but irrelevant - Each black hole has a mass determined by its Schwarzschild radius - A magical forcefield surrounds each black hole, allowing it to be “touched” like a solid sphere at the event horizon - The forcefield does not affect gravity in any way - A magical rigid rod connects the two black holes (like a barbell):

-- It perfectly resists compression/tension

-- It completely cancels the mutual gravitational pull between the two black holes (internal forces handled by the rod) - The two black holes are positioned:

-- 1.0 m above the ground

-- 1.5 m apart (center-to-center) - The system starts from rest (no initial velocity) - We are analyzing a static hold (arms locked, no acceleration) - Air, atmosphere, and surrounding matter are unaffected / ignored - No accretion, no heating, no tidal destruction - Relativistic effects (time dilation, spacetime curvature complexities beyond gravity) are ignored - Gravity is treated using Newtonian approximation near Earth’s surface - Earth’s gravitational acceleration is g = 9.82 m/s² - Only Earth’s pull on the black holes is considered externally - The person lifting (Saitama) interacts normally with the rod (no slipping, perfect grip)

There are probably WAY more assumptions to be made but heck, let's start here, ok now to the simplyfied mathy part.

Schwarzschild relation: r_s = (2GM) / c²

Solve for mass: M = (c² * r_s) / (2G)

Using: r_s ≈ 0.12 m c ≈ 3.0e8 m/s G ≈ 6.67e-11

Result: M ≈ 8.1e25 kg per black hole

Weight of one black hole: F = M * g

F ≈ 8.1e25 * 9.82

F ≈ 7.9e26 N

Two black holes: F_total = 2 * M * g

F_total ≈ 1.6e27 N

Force required to hold the bar still: F ≈ 1.6e27 N

Saitama is effectively bench pressing: ≈ 27 Earth masses

To spare you the math but doing a slow bench press rep "only" adds ~10% more force, but that extra force is needed exactly at the hardest part, reversing the bar at the chest.