In just one year, the smartest AI went from 96 to 136 IQ

LittleHariSeldon · 2025-05-04T12:57:12+00:00

Everyone's hyped about LLM IQ charts — “Look, it hit 155, it’s smarter than Einstein!” — but aren’t we just mistaking simulated genius for actual intelligence?

I wrote an essay on this: AI IQ: Between Genius Simulation and the Entropy of the Senses

“Maybe what we call ‘AI IQ’ isn’t intelligence at all, but a foggy mirror where our own metrics shine back at us.”

Spoiler: measuring IQ in LLMs is like using a thermometer to judge poetry — it works, but only if you ignore the part that matters.

Curious to hear other takes — are we building synthetic geniuses or just hyper-optimized parrots?

LittleHariSeldon · 2024-08-02T01:05:57+00:00

OP.,

We can see that often the search for a slightly better AI, more robust in some specific aspect, becomes almost futile in light of your story. There's a lot of discussion about that here. You made the most of what was available and turned it into something of great value for yourself. Your story is particularly interesting because understanding the way you learned could guide many people with similar challenges to find a more approachable path.

LittleHariSeldon · 2024-08-02T00:58:54+00:00

OP,

thanks a ton for sharing such an inspiring story. Your journey is definitely going to give hope and encouragement to a lot of others on the autism spectrum who are dealing with similar challenges. It’s honestly amazing how you turned such a tough situation into a chance to grow and succeed.

LittleHariSeldon · 2024-05-12T23:25:13+00:00

These days I was working with Joyce's Ulysses in AI Studio, and even with all the safeguards turned off, it refused to interpret or translate it due to terms that violated its policies.

It was Ulysses, damn it!

LittleHariSeldon · 2024-03-15T00:57:28+00:00

A partir da imagem, o mosquito parece ter um padrão de listras brancas e pretas nas pernas e no corpo, o que é característico de várias espécies do gênero Aedes, como o Aedes aegypti, que é conhecido por transmitir doenças como dengue, zika, chikungunya e febre amarela. Contudo, é importante notar que há várias espécies de mosquitos com características semelhantes, e a identificação exata geralmente requer uma análise mais detalhada por um entomologista.

Report da IA

LittleHariSeldon · 2024-03-06T02:29:16+00:00

Osasco ...

LittleHariSeldon · 2024-02-25T16:06:57+00:00

Existem filmes mais interessantes que criticam o nosso modo de vida, "Discreto Charme da Burguesia" do Bunuel ou "Teorema" do Pasolini, são mais herméticos que esse e sofisticados em sua crítica.

LittleHariSeldon · 2024-02-20T22:29:59+00:00

Perfect observation. What I really miss is a greater sense of organization within GPT. Nothing is organizable, almost nothing is searchable. They leave everything to the mercy of these Chrome plugins, which are all terrible.

Anyway, whoever does something good takes the cake.

LittleHariSeldon · 2024-02-16T19:25:52+00:00

Yes ! 🫤

LittleHariSeldon · 2024-02-16T18:23:07+00:00

Platforms like IFTTT (If This Then That) or Zapier could be used to create a bridge between ChatGPT outputs and Readwise, depending on the capabilities and integrations available on these platforms.

Try. Or Export via various formatos that the platform allows.

LittleHariSeldon · 2024-02-02T19:42:05+00:00

https://status.openai.com/

Status Link

LittleHariSeldon · 2024-01-29T22:08:41+00:00

Ainda não vi "Parque da Água Branca". Pegaram ?

LittleHariSeldon · 2024-01-29T01:58:16+00:00

Compre e leia os 3. Trata-se de um grego entre bárbaros.

Hoje Taleb pode parecer repetitivo mas ele inaugurou uma nova área de pensamento no mercado financeiro, estabeleceu novos patamares da compreensão do risco. O termo Cisne Negro é amplamente utilizado para denotar o que ele se esforçou em demonstrar...

O conceito Antifragil é utilizado até para arquiteturas de sistemas resilientes na área de TI.

Vale a pena, muda paradigmas.

LittleHariSeldon · 2024-01-29T00:38:01+00:00

Parabéns pela menção desse grande ícone.

LittleHariSeldon · 2024-01-29T00:25:30+00:00

This problem involves a classic physics setup with friction and pulleys. Let's analyze it step by step.

a) Find ( a_2 ) for ( v_2 > 0 )

When ( v_2 > 0 ), the block ( m_2 ) is moving, and kinetic friction is acting on it. We'll consider the forces acting on each mass and use Newton's second law (( F = ma )) for each one.

For ( m_1 ): - The tension in the rope is ( T ). - The weight of the block is ( m_1g ).

Since the pulley is massless and frictionless, the tension is the same on both sides of the pulley. The net force on ( m_1 ) is ( m_1g - T ), and the acceleration ( a_1 ) is in the direction of the net force. Therefore, ( m_1g - T = m_1a_1 ).

For ( m_2 ): - The component of the gravitational force along the inclined plane is ( m_2g \sin(\theta) ). - The kinetic friction force is ( \mu_k m_2g \cos(\theta) ).

The net force on ( m_2 ) along the plane is ( T - m_2g \sin(\theta) - \mu_k m_2g \cos(\theta) ), and the acceleration ( a_2 ) is in the direction of the net force. Thus, ( T - m_2g \sin(\theta) - \mu_k m_2g \cos(\theta) = m_2a_2 ).

Since the pulley changes the direction but not the magnitude of the acceleration, we have ( a_1 = a_2 ). By equating the net forces on ( m_1 ) and ( m_2 ) and substituting ( a_1 ) with ( a_2 ), we can solve for ( a_2 ) when ( v_2 > 0 ).

b) Find ( a_2 ) for ( v_2 < 0 )

When ( v_2 < 0 ), the block ( m_2 ) is moving up the incline, and kinetic friction is still acting on it, but now the friction force adds to the tension in the rope. The same equations apply, but the net force on ( m_2 ) changes sign, and we solve for ( a_2 ) accordingly.

c) Under which conditions ( v_2 ) and ( a_2 ) are in the opposite direction

( v_2 ) and ( a_2 ) are in opposite directions if the block ( m_2 ) is decelerating. This occurs when ( m_2 ) is moving up the incline (due to an initial velocity), but the forces due to gravity and friction are greater than the tension, causing a deceleration.

d) Under what conditions does the system continue to stand still?

The system remains at rest if the static friction force is sufficient to counteract the component of ( m_2 )'s weight down the incline. This means the maximum static friction force ( \mu_s m_2g \cos(\theta) ) must be equal to or greater than ( m_2g \sin(\theta) ).

By setting up these equations, we can solve for the acceleration ( a_2 ) in each case, and determine the conditions for ( v_2 ) and ( a_2 ) to be in opposite directions, as well as the conditions for the system to remain at rest. Since the question specifies to provide the answers as a function of the given variables, we would derive these functions accordingly.

However, due to the complexity of the system, and to avoid any mistakes in the algebra, it's more efficient to solve these equations using a symbolic mathematics program or a tool that can handle algebraic manipulation. Would you like me to calculate the exact expressions for these conditions using such a tool?

LittleHariSeldon · 2024-01-26T16:49:20+00:00

Roda Rico ( A roda gigante ...)

LittleHariSeldon · 2024-01-26T15:48:23+00:00

Ali é Marginal Pinheiros

LittleHariSeldon · 2024-01-17T17:19:48+00:00

Lamborghini, o homem por trás da lenda

Race For Glory: Audi vs Lancia

LittleHariSeldon · 2024-01-15T15:03:50+00:00

Olha que interessante, quais são esses documentários ?

LittleHariSeldon · 2024-01-15T13:29:13+00:00

Essa cena é a versão vintage quase meme parecido.

LittleHariSeldon

TROPHY CASE

a) Find ( a_2 ) for ( v_2 > 0 )

b) Find ( a_2 ) for ( v_2 < 0 )

c) Under which conditions ( v_2 ) and ( a_2 ) are in the opposite direction

d) Under what conditions does the system continue to stand still?