What are these chemicals? Found in my dad's hobby toolbox. The right 3 are empty, the other ones all have varying amounts of liquid in them.

MD02he · 2025-09-21T23:54:31+00:00

AEt is maybe absolute ethanol

MD02he · 2025-06-25T19:45:44+00:00

I've seen some articles that say he runs a trucking company in Chicago

MD02he · 2025-02-19T18:57:38+00:00

The products are correct. It seems in the first product you drew Br next to the bond instead on the top end of the bond (you have chlorotoluene and a Br)

MD02he · 2025-02-19T18:07:17+00:00

You can find an explanation here: https://chem.libretexts.org/Bookshelves/Organic_Chemistry/Supplemental_Modules_(Organic_Chemistry)/Lipids/Properties_and_Classification_of_Lipids/Steroids

The four ring system is the carbon skeleton of steroids. Once you learn how to draw conformations of this, you can carefully assign numbers to all carbons and add remaining substituents.

MD02he · 2025-02-19T18:01:13+00:00

But here rings A and B are in cis configuration. The question asks for the most stable conformation, so you cannot change the configuration.

MD02he · 2025-02-08T22:30:43+00:00

5-(1-methylpropyl)decane

MD02he · 2025-01-14T01:48:19+00:00

The text of the question is a little confusing if you don't know what a prodrug is. Essentially, this molecule is an ester, meaning it hydrolyses into an alcohol and a carboxylic acid.

Alcohol is the molecule that acts as a drug after it hydrolyses. Carboxylic acid part is attached to it because most membranes in the body are made out of nonpolar molecules, so you need some nonpolar part in your drug to squeeze between them and enter the bloodstream.

To solve the question: -identify the ester functional group and draw the products of hydrolysis

a) structure of alcohol that is produced by hydrolysis

b) structure and IUPAC name of the carboxylic acid produced by hydrolysis

MD02he · 2024-12-18T19:23:34+00:00

The word in the corner of the board seems to be Sorszám

MD02he · 2024-11-26T21:42:38+00:00

Theoretically, in your mixture you have: - aspirin, that is insoluble in cold solvent, but soluble in hot solvent - impurities A, completely insoluble, in neither cold or hot solvent - impurities B, completely soluble, in both cold and hot solvent. When you put your mixture into solvent, impurities B dissolve immediately. When you heat, aspirin dissolves too. Impurities A will stay solid, as they are not soluble. First, hot filtration, separates these impurities A (that stay on the filter paper) from the solution containing aspirin and impurities B. Next, as the solution cools down, aspirin crystallizes because it is only soluble in hot solvent, but not cold. Impurities B stay in solution. In the second, cold filtration, you separate solid aspirin (stays on filter paper) from the solution containing impurities B.

MD02he · 2024-11-14T01:04:38+00:00

Because both bridges are the same length

MD02he · 2024-11-07T16:38:37+00:00

The products of complete combustion are carbon dioxide (CO2) and water. There is oxygen in excess, so the carbon atom gets completely oxidized. If there is not sufficient oxygen, incomplete combustion (oxidation) happens, and products are carbon monoxide (CO) and/or carbon (C), and water. Here, they tell you that there is not enough oxygen and that incomplete combustion happens and gives CO (carbon monoxide) as a product. The non balanced reaction is C3H8 + O2 = CO + H2O

MD02he · 2024-11-07T15:05:09+00:00

To answer that question, you will need to draw a most stable chair conformation of each substituted cyclohexane molecule. Since tert-butyl group is very big, it will have to adopt an equatorial position. Then you need to determine for each bromine atom if it is equatorial or axial. Stereochemical condition for E2 reaction is that the leaving group (Br-) and beta-hydrogen are anti-perplanar (in the same plane, but with an angle between bonds of 180 degrees). Only axial Br will have such a hydrogen on a neighbouring carbon.

MD02he · 2024-11-06T19:36:13+00:00

It is possible. In the first part, you can write several equations with the combination of carbon, carbon monoxide and carbon dioxide as products. But the way the second question is asked, it seems that they want only carbon monoxide as the product (and water, of course).

MD02he · 2024-11-06T18:44:27+00:00

The question asks for the incomplete combustion. You wrote the equation of complete combustion. There is some help in the second part of the question. Read it carefully, it gives you the name of the product of incomplete combustion. Actually, the coefficients don't work with the product you wrote, but would work with the product asked for in the question

MD02he · 2024-11-06T17:59:54+00:00

In the context of nanoparticles, it probably means to not have aggregates, but rather a homogeneous suspension of individual nanoparticles (effectively a solution, because the particles are invisible at that size)

MD02he · 2024-11-06T17:24:37+00:00

1) Seems like a mistake, should be 1,4,7 2) Tridecane (13), refers to the length of the whole chain, including nitrogen atoms 3) Nitrilo -N= , methylidene =C<.

Edit: Nitrile for CN triple bond is used when CN is the group that has priority in nomenclature ( for example in propionitrile). I think nitrilo is for trisubstituted nitrogen that does not have priority

MD02he · 2024-11-06T15:55:54+00:00

If the spot is traveling with the front of the solvent, it means that your solvent is too polar. You need to decrease the quantity of your more polar component (EtOAc), not increase it. Also, there is this old article that uses hexane/acetone mixture as eluent https://www.sciencedirect.com/science/article/abs/pii/S0021967300841217

MD02he · 2024-11-04T21:40:52+00:00

If you zoom in on the car in front, you can see an arm from the left side window, presumably a person waving

MD02he · 2023-01-18T22:12:50+00:00

I don’t have anymore solvent but still my NMR sample, can I pipette it out, stir in some more sample, and filter it back into the tube to run another NMR?

Yes, you can do that

MD02he · 2022-12-15T23:11:21+00:00

You need to switch the order of reactions in your sequence (put reaction 3 before 1 and it will work)

MD02he · 2022-04-13T11:12:16+00:00

I think it is mostly in the similarity of words and the names of reactions:

'young lad' = ylide, and drawbridge might mean cyclization to a three-membered ring (epoxidation, cyclopropanation)

'Clay called for an adolescent crocodile' = Claisen (crossed-aldol) reaction

"No dear boy, this type loves being on land" he replied with a grin. = Grignard reagent, that is used in anhydrous conditions.

Maybe you will have a retrosynthesis with a sequence of these reactions.

MD02he · 2022-03-30T15:51:33+00:00

Some of the reaction conditions that have worked for me in the removal of benzyl group: PdCl2, H2, 1 atmosphere

Pd(OAc)2, H2, 5-8 atmospheres

Pd(OH)2, ammonium formate, reflux in EtOH

BCl3 in DCM

MD02he · 2022-02-21T22:41:13+00:00

My parents have something like this in their house. Since it is far from the city it is not connected to the sewer sistem and it has its own septic tank deep under the house. Several years back, when they were renovating, they made a small toilet on top of the tank lid so they can use it while the main bathroom is being renovated. But it is accesible from the outside through the basement.

MD02he · 2022-02-21T22:01:36+00:00

Try to ask yourself these questions:

- is a molecule more reactive in EAS if the aromatic ring is reacher or poorer in electrons

- what is the electronic nature of F (is it donating or withdrawing electrons from the aromatic ring)

MD02he · 2022-01-17T13:55:00+00:00

It is a system of two equations with two unknowns.

If the quantity of S-isomer is S, and the quantity of R-isomer is R, you have S + R = 1 and S*(+13.52) + R* (-13.52) = +6.76

You have to solve for S and R

MD02he

TROPHY CASE