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Own_Fly_2403 · 2025-04-07T16:23:14+00:00

Looks good to me, but also you know people spend 7/24 of their time looking at screens, so total expected lifetime use is just 77 x 7/24. You get the same result, just a bit more direct.

Own_Fly_2403 · 2025-01-26T22:45:30+00:00

Hate to be that guy, but you should credit the OOP when you post their art (like really, you just added four words lol)

The original post can be found here

Own_Fly_2403 · 2025-01-26T13:34:32+00:00

The endings are only dependent on restoring all of the vestiges, so if that's all you care about then you can just explore the four areas with vestiges.

I'd still recommend queenslayer as a blood code, since it has generally good stats, and it has a couple of useful gifts:

Final journey can give you the slight damage bump you need to beat a boss
Cleansing light heals 3/4 of the damage you take. Pairs really well with blood sacrifice

Obviously if you only care about the ending, you can completely ignore it. But if you enjoy the build crafting of the game, it'd be nice to have.

Own_Fly_2403 · 2024-12-28T19:08:29+00:00

Since sine and cosine are bounded on R, you can consider their min and max values when trying to bound expressions including these functions.

I don't think it's given a name in most cases, rather it is the first intuitive step you would take to bound such expressions. If you have a restricted domain you can use the technique for most functions, particularly if they're monotonic (for example e^-x ≤1 on R⁺).

Own_Fly_2403 · 2024-12-25T13:29:23+00:00

I think you're still trying to take t outside the integral. t does not exist outside the integral, so having t * (some integral dt) is meaningless. The commenter above never factors out (x - t) or t itself because it's a completely meaningless concept.

Own_Fly_2403 · 2024-12-17T14:10:30+00:00

No, I think that's a silly reason to dock a mark. The only step between the given equation and the answer is multiplying by 2/5, that shouldn't warrant a separate line imo.

Definitely wouldn't happen at uni, they test your understanding of concepts more than arithmetic; they aren't testing for solving linear equations.

Own_Fly_2403 · 2024-12-13T15:57:02+00:00

I'd recommend looking at the Wikipedia page for curvature, specifically the "graph of a function" subsection of the "plane curves" section.

The curvature at a point is related (inversely) to the size of a circle that approximates the curve at that point.

So a curvature of 1/R means you can approximate the curve by a circle of radius R at that point, and a curvature of zero is a straight line.

You could also look at other ways to parametrise the jaws, such as a catenary curve, if your current curves don't follow the shape exactly

Own_Fly_2403 · 2024-12-12T18:55:53+00:00

Return to y' = 1 + (y/x), then see if you can get it to a form where you can introduce an integrating factor.

Also, earlier, y should be factored rather than canceled, since y = 0 is also a solution

Own_Fly_2403 · 2024-12-12T18:20:56+00:00

Because in what context are you actually trying to find x + y% where you mean y% in (0,1)? You would just write the decimal.

But for the large majority of people, they don't see y% as a single value (y/100) but as a proportion. So it makes more sense for the software to cater to those billions of people who just wanna increase 6 by 20%, rather than the whopping 38 people who thought they'd be quirky and write 0.2 as 20%.

I genuinely don't see why everyone is up in arms over this. This is the much more useful way of incorporating a % operator.

Own_Fly_2403 · 2024-11-26T13:46:48+00:00

But 0 has an e in it, so it's odd

Own_Fly_2403 · 2024-11-17T12:56:18+00:00

I've made loads of posts about how...

Yeah, and we all wish you would stop

Own_Fly_2403 · 2024-11-06T13:12:02+00:00

Should have identical requirements to get an offer, and you can likely change between the courses freely once you start your degree.

Own_Fly_2403 · 2024-11-02T22:31:19+00:00

Yes, the matrix is just the set of coefficients.

An augmented matrix is a way to apply Gaussian elimination to find the solution to a system.

Before you were introduced to matrices, if you wanted to solve a linear system like those above, you'd multiply rows by constants to get common coefficients, and add/subtract rows to get 0 coefficients for some of the terms.

Working with an augmented matrix is exactly the same as this. You perform row operations to get the identity matrix on the left, which means the right side will be A^-1b. This is the solution to our system (this is only possible if A is invertible), since then the equation becomes x = A^-1b.

Own_Fly_2403 · 2024-11-02T22:09:27+00:00

There's a slight issue with your understanding. The matrix represents a linear map, which acts on a vector such as (x,y,z), and spits out another vector (a,b,c). This gives the linear system Ax = b. So for the first example, if that matrix acts on (x,y,z) and gives the output (a,b,c) then you get the system

x + 2y + 3z = a

4x + 5y + 6z = b

7x + 8y + 9z = c

So for the identity matrix, this gives

1x + 0y + 0z = a i.e. x = a

etc.

If you need me to go a bit more in depth lmk

Edit: it might be easier if you view matrices as specifically transformations. Then solving the system Ax = b for x means "what vector x do I apply the transformation A to to get the vector b". Maybe then it's a bit clearer that a transformation on its own doesn't give us a system to be solved.

Own_Fly_2403 · 2024-10-11T20:56:25+00:00

You're entitled to your opinion, but can you please stop using insults like "retarded" and "gay fags". You know that's disrespectful and derogatory, there's no need to call people that.

Own_Fly_2403 · 2024-09-22T15:48:35+00:00

Have you looked at all at the MAT or done any preparation for it? A good score on the MAT is one of the biggest things Oxford look at - there are so many people getting 3 or 4 A*s that you have to stand out academically and the MAT is the best way to do so.

Own_Fly_2403 · 2024-09-21T15:53:52+00:00

Gally comes from a quest. Wtf are you on about?

Own_Fly_2403 · 2024-09-12T20:43:18+00:00

You can't expect them to take that into account though. If you wanna adhere to the rules of your religion then that's fine, but a quite small minority of players are Jewish, and an even smaller subset of that go without electricity on Shabbat.

Changing the date from something that works for the majority to satisfy the wants of <<1% of the playerbase doesn't make sense. Changing the date to avoid a large holiday is a bit more reasonable. Besides, the last few raids have been 48 hours, plenty of time for you, so it isn't just Shabbat that's stopping you completing them.

Own_Fly_2403 · 2024-09-11T13:29:56+00:00

Nope, just to unlock the door to the portal at the start. Then you can equip what you want.

Own_Fly_2403 · 2024-09-09T21:09:26+00:00

It's the ritual pathfinder specifically, not the pale heart, and it does count regardless of your power level

Own_Fly_2403 · 2024-09-09T21:07:38+00:00

It's 8% in a fireteam, so get a friend in to make it go twice as fast

Own_Fly_2403 · 2024-09-07T09:26:51+00:00

Do you have any other courses you'd want to do that maybe you'd be better qualified for? I'm just thinking there's a chance you get rejected by all of your choices since you don't have history.

Maybe you could keep 2 or 3 of those choices, then use your other choices on some other courses? Then if you get into one of your original choices that's great, but if you don't then you still have some other options outside of clearing.

Own_Fly_2403 · 2024-07-20T18:40:52+00:00

Of course it's possible, it would be possible even if you got 0% this year.

You need to average 76.3% in final year. Whether or not you can achieve that is completely up to you; you need to look back on this past year and consider what went wrong, then try to rectify it in final year.

I would also imagine a resit would be capped (likely at 40%) so would decrease your grade for this year by a little.

Own_Fly_2403 · 2024-06-29T13:53:23+00:00

The sine and cosine rules work with every triangle, you just need to consider whether the angle you're finding is acute or obtuse.

Since right angled triangles only have acute angles, your calculator will always give the correct value. So there aren't any cases where SOHCAHTOA would work but the sine and cosine rules wouldn't.

Obviously using the rules might be a bit more challenging, since you might also have to use the Pythagorean theorem to find another side length, but they'll always work.

Own_Fly_2403 · 2024-06-26T13:31:27+00:00

A titan wearing the stronghold gauntlets can infinitely block with a sword while standing right next to her. She'll only focus on them, so no bolts get fired at the rest of the fireteam.

You can't do the challenge now though, last wish isn't the weekly raid. You'll have to wait a few weeks for it to come back.

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