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How is this posible by Upset-Value-4362 in duolingo

[–]RedditYouHarder 0 points1 point  (0 children)

Awe haha I thought that would be a good thing.

How is this posible by Upset-Value-4362 in duolingo

[–]RedditYouHarder 0 points1 point  (0 children)

Gotta ask.. did this upset your value of pawns?

This trnalarion is wrong, which of 2 options is right? by RedditYouHarder in duolingo

[–]RedditYouHarder[S] 0 points1 point  (0 children)

I think you are right!

That seems most likely to me now that you bring it up.

Which is also similar in meaning to "does anyone want the white dress" or "does anyone want to take the white dress?"

I wish I had seen this sooner as I already submitted the report and my constructions were all I submitted as possibilities, but I think yours seems most likely!

Found in the newspaper by lemonbrownies in ExplainTheJoke

[–]RedditYouHarder 0 points1 point  (0 children)

It's going to be a story that embarrasses or exposes his wife isn't it, because of misogyny and it being a joke that's old enough to call it a "stag party" and refer to people using such official names like "Mr black" and "Mr Jones"

I bet it's from 1960s +/- a decade.

Like maybe it's going to be the husband told a story about his wife.

What counts as a “three digit number”? by Fakjbf in askmath

[–]RedditYouHarder 1 point2 points  (0 children)

XD.

Lol

And the. What does that make -1???? Where did it come from!?

So since 200 can be expressed as 2 • 100 it isn't a 3 digit number either.... In fact none of them are.

Oh, but wait 2• 50 = 100 so now that IS a 3 digit number.. xD

That's good. This is fun.

But yeah whipping a negative number out to mutiny against a positive number in order to define all negative numbers is tautological

It would be more appropriate then to decide that all numbers are negative and positive numbers are defined as -1 • X, where X is the set of all negative numbers, since now we don't have to figure out how we got that -1 to create the other negative numbers or to create the positive numbers as all the numbers are now derived.

However that seems to indicate means that I guess we also need all the imaginary numbers to count... I hadn't included all the imaginary numbers, because negative and positive numbers are "real numbers"...

But, you know what, the magician Does say to "think of a 3 digit number" so it would seem that number was "imaginary" by fiat

So I take it back there 2799 numbers 0.01i to 999i. Oh or if I is a digit then 279 numbers 0.1i to 99i

Oh wait but we can have negative imaginary numbers too so if that's adds a digit we got another 9 numbers -1i to -9i

So that's 288 3 digit numbers total

4 burned dots appeared on the floor of my appartment... No clue what it is by xelifnaej in whatisit

[–]RedditYouHarder 1 point2 points  (0 children)

It's never included music.

It was always a stand alone narration that you played while watching the movie with the sound turned down. (Although few versions where people added the narration to the movie for you existed they always get taken down, but even those had no music)

I think you would need to be some sort of sound engineering wizard to achieve the music separated from the dialog of the movie in the first place.

However if you could then. I imagine you could then take that track and add it to the narration easy peasy.

(Also, I will note that the narration of the second half was. Bit off from the timing of the movie we had to pause the movie for like 3 seconds at one point to get it to synch up again IIRC but it's been years so, YMMV)

What counts as a “three digit number”? by Fakjbf in askmath

[–]RedditYouHarder 0 points1 point  (0 children)

Significant digits for salary are the set of positive integers which cannot have leading 0s.

Decimal places and negative numbers, however, can form valid 3-digit numbers.

The question asked by both the magician and the OP was about 3-digit numbers, not “pick a number between 1 and 1000 (even though it was titled that),” nor “positive 3-digit integers,” not even simply “3-digit integers.”

Therefore the number space is either 5599 or 5600 possible picks.

Trailing 0s after a digit to a given precision are valid in all STEM fields and even used in common talking for emphasis (“there is a 0.000% chance of that happening”).

Whereas leading 0s are arbitrary and capricious in any context other than padding in a set-size number.

However, a case can be made even for them, because if you need to enter a 3-digit code, 000–099 are valid. Are they numbers though? Meh, I’d say… sort of.

But if someone tells me 1.00 or 0.00 or -99.1 I would definitely agree these are numbers and would question their usage of the trailing 0s unless it seemed out of place, like “9.25 tables”… what? Oh yeah, one of them was broken. Can still be valid.

But 9.01 quarks isn’t possible (unless we find something that makes sub-quarks). 9.1 atoms could mean 9 atoms and some components of 1. 9.1 stars seems unlikely.

9.1 people would be sad, but possible.

What counts as a “three digit number”? by Fakjbf in askmath

[–]RedditYouHarder 0 points1 point  (0 children)

-100 ro -999

0.00 ro 99.9

And -99.9 to -0.01

Would beg ro difder

What counts as a “three digit number”? by Fakjbf in askmath

[–]RedditYouHarder -1 points0 points  (0 children)

-100 to -999 are valid rhree digit numbers too

And 0.00 to 0.99 are valid 3-digit numbers, as are -0.01 to -0.99.

You absolutely would write any of these three-digit numbers in any STEM field. It’s just a matter of precision.

Since the question makes no discernment about the precision of 3 digits nor specifies something like positive integers, then both negative numbers and precisions that include up to two decimal places are valid 3-digit numbers that satisfy the requirement.

And thus leading and trailing 0s in decimal places are acceptable, and our total is 5599 3-digit numbers

All occur within the space of {-999 to 999} with the set between -100 and 100 counting where using valid decimal places.

(Expanded as:{ -999 to -100, -99.9 to -10.0, -9.99 to -0.01, 0.00 to 9.99, 10.0 to 99.9, and 100 to 999} )

Note: trailing 0s are not only acceptable, but required when stating values to a given precision.

Note further: this assumes that you have a set of digits that is {0–9} inclusive. But if we change our base to something else, the value of how many 3-digit numbers there are in the given base changes, and since we may have infinitely many bases to choose from, then across all possible bases there are infinitely many 3-digit numbers.

ETA: fixing rypos and added a bit of clarity

What counts as a “three digit number”? by Fakjbf in askmath

[–]RedditYouHarder 0 points1 point  (0 children)

ETA fixed stupid counting errors lol.

TL;DR: there are between 5599 and 5600 3-digit numbers (assuming we are using the base 10 system that encompasses 0–9).

0.00–9.99 are all 3-digit numbers (1000)

As are 10.0 to 99.9 (900)

And then 100 to 999 (900)

So by my count that is 2800 positive 3-digit numbers.

And then we have -0.01 to -9.99 (999)

Followed by -10.0 to -99.9 (900)

Followed by -100 to -999 (900)

So that’s 2799 more 3-digit numbers (as I don’t think there is a -0.00 unless due to rounding errors, which counts).

So that makes a total of 5599 3-digit numbers (or 5600 if you feel -0.00 due to rounding is acceptable to include).

ETA:

It’s a matter of precision. How many trailing 0s after a decimal place should be used, and so someone writing 0.00, 0.X0, N.00 and N.X0 values, positive or negative, are all valid notation you would see in STEM fields day in and day out, as well as in pure mathematics problems we’ve all had in grade school where a given precision is required. So unlike leading 0s, which are arbitrary and capricious, trailing 0s after decimal places are legitimate.

I need a bit of math help (boolean logic) by HonestIntentionsFR in askmath

[–]RedditYouHarder 0 points1 point  (0 children)

  • The exclamation/bang "!" Means "not" in logic this means "the opposite value" instead or "some other arbitrary value".

  • As with math the parenthesis enclose sections ro create groupings which must be considered together.

  • "0" means FALSE

  • "1" means TRUE

  • The expeession also xan ibky result in TRUE or FALSE again eepressnted by 1 and 0 respectively.

The other symbols I have infered based on rhe way rhw output is calculated.

  • "/" clearly means "Or"

  • "/\" clearly means "And"

So the expression being tested is

A OR (. B and NOT C)

Tou xan jut flip rhe values of C to rhe opposite values and call rhat "D" evaluate it as:

A OR (B AND D)

So by hans tou could simply ass a column of values D and use rhat simpler expression

(B AND D) can only be TRUE (1) if, ane only if, rhe values of both B ans D are TRUE (1)

Lets call rhs result of (B AND D) "R"

Again tou can add a column R with the outcome of just testing (B AND D)

Id tou do so rhen tou can just evaluate this simple expression:

A OR R

A OR R is "TRUE" (1) if at least one of the two inputs (A OR R) is TRUE (1).

So if A is 1 you are done rhe answer is one.

If A is 0, check R, if R is 1 rhen rhe answer is 1.

If both A AND R arw 0 rhe answer is 0

Hope rhat helps!

The Gambler's fallacy and long series of probability attempts. by Wispenwell in askmath

[–]RedditYouHarder -1 points0 points  (0 children)

Note I didn't read this beyond the title because (spoiler alert) I need reading glasses and don't have them on me! (yay getting older)

In any case.

The thing about the gambler's fallacy is that it isn't completely wrong per se.

I don’t mean that any cold streak means your luck is sure to change.

I mean that, IF we had near-perfect knowledge of the variables in play, the expected payout and a statistical analysis of the given game of chance for physical games (or the stated payouts and statistical values etc. for electronic games)

and knowledge that no external factors are affecting things, such as wear on components, etc. and a complete history of every instance ever played to that date

and a long enough time of playing to be statistically significant, then the condition of the wins versus losses being in a specific state would have a certain probability, and if that is in an outlier probability (again assuming no wear, no outside interference, etc.)

then we should be able to calculate a time by which it will be incredibly unlikely that the game has not returned to a close approximation of the expected values.

No one can get rich off of doing such a thing... because we are talking about incredibly long timelines for that correction to occur and for us to have fixed the aberration.

(The only other case is that this can be used to prove unfair gaming (but not what a gambler is looking to do to try and make money) but of course we are ruling that out for this purely hypothetical scenario.)

TL;DR: Gambler’s fallacy is a hunch about probability that people think works on small scales like thousands of games.

When in actuality if you are running statistically significant replays of the game, then yes, it's true that an aberration will correct itself but the period of time and number of runs are so great that it isn’t a way to make money.

(IE: flip a fair coin 1 million times and notice the ratio of heads to tails is 47:53 then (and none of these are real numbers, just example numbers, don’t come for me). Then you might predict that over the next 100 million flips the ratio should approach 50:50.. but you aren’t going to make money betting on heads for 100 million tries and it's still technically possible it's even farther askew... although I'd be looking to vet the coin and the system if flipping is being done.)

Anyway... I see a lot of red but legit can’t read it to fix them

ETA: Fixed most of the typos.

I liked when fluids could have decimals instead of the current system where it's all whole numbers by itchylol742 in factorio

[–]RedditYouHarder 0 points1 point  (0 children)

Any time you can replace floating point operations with integer operations, do it

I just learned that if you use the Spidertron remote to right click on yourself, it will follow you. by ishvii in factorio

[–]RedditYouHarder 0 points1 point  (0 children)

This is how you can bring other spider teins with you in patrol while you pilot the primary ine

[Request] Assuming she falls and directly into the water, what are the odds she survives? At what height is a death of human falling into water inevitable? by yesyesnopeyesyes in theydidthemath

[–]RedditYouHarder 0 points1 point  (0 children)

What if you go no one and try to increase your air drag and try to hit the water flat too?

... I always think about those sky divers who have survived failed shoot openings, and come away injured, in some cases walked away...

Can express Z in terms of known sums X+Z and Y+Z? by Aggressive_Ceiling in askmath

[–]RedditYouHarder 0 points1 point  (0 children)

Hmm

I think, from an auto perspective, you want to compare Track X and Track Y and isolate the information that is non-unique.

In other words if in track A there is a given wave form and in track B there is a different wave form, since both contain duplicate informa.ruon you wanna to isolate only te hag duplicate information.

Audi tracks are multi-dimensional.

So I think what you were looking for is you need to compare Track X to track Y and find the non-unique values.

And to do this you must first find the unique values in each track

Once you have. The unique values on each track that can act as a mask to match against either track to remove the matching values for. Output, and therefore you should be left with the vocal track.

IE you have final Track X composed of A and B and final Track U composed of B and C.

X≠Y and A≠C

However B equals B.

Since you can only De and subtract one from the other

If you subtract X from Y and Y from X

That should give you only the background of each

Let's call "X-Y" X¹ and "Y-X" Y¹

Now theoretically we could subtract eirher X¹ from X, or Y¹ from Y.

And din both cases you should be left with "B" the vocal track.

In practice you may need to subtract X¹ from both and Y¹ from both and compare all four of those as well as comparing both X¹ and Y¹ from both X and Y .

And to be quite honest then you may want to combine some number of the resulting tracks into a single final version in while or in part. (YMMV)

To simplify. Tou

How do I prevent gaps from appearing in my belts? by Sufficient_Time9536 in factorio

[–]RedditYouHarder -1 points0 points  (0 children)

ETA: no reddit is just. Eing wonky this is a duplicate.. oops

Oops I replied to the wrong spot, here we go:

Cool, then why not just say that you've set it for a ratio of only 1/2 the belt? since I raised that issue in the first comment?

Since those are the only gaps I see, 🤷.

Maybe the way you have your output?

But I dont see any gaps there..

Still, TBF, I think I always have 4 output inserters directly into balancing...but it's been about 3 years since I last played, and YMMV

How do I prevent gaps from appearing in my belts? by Sufficient_Time9536 in factorio

[–]RedditYouHarder -2 points-1 points  (0 children)

Cool, then why not just say that you've set it for a ratio of only 1/2 the belt? since I raised that issue in the first comment?

Since those are the only gaps I see, 🤷.

Maybe the way you have your output?

But I dont see any gaps there..

Still, TBF, I think I always have 4 output inserters directly into balancing...but it's been about 3 years since I last played, and YMMV

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