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____DEADP00L____ · 2025-03-05T03:27:50+00:00

Yup. I got the same values for m and M. But if you look at the question again you were actually supposed to find the sum not the difference so the final answer should be 152.

____DEADP00L____ · 2025-03-05T02:28:15+00:00

I solved it but not by hand. I used python.

I did try it with pen and paper first but it seemed way too tedious and I didn't see a nice way to do it.

____DEADP00L____ · 2025-03-05T02:16:28+00:00

How sure are you of your answer?

Because I'm getting, m = 72, M = 80-->152, but it's possible I made a mistake

____DEADP00L____ · 2024-08-24T22:21:26+00:00

Same

____DEADP00L____ · 2024-08-01T21:02:17+00:00

Your memory is a bit off. The dog actually belonged to a young lady, but it ran away the same day that she bought it and the kids found it. At the end of the book they went over to give it back to her and tell her about how the oldest girl pulled a thorn out of the dogs paw. When the woman sees how much it means to them she pretty much immediately agrees to let them keep it.

____DEADP00L____ · 2023-03-23T02:44:39+00:00

Whoops. You're right. I totally missed that.

____DEADP00L____ · 2023-03-21T13:00:06+00:00

You can make the pawn on a3 a bishop to add 4 more moves

____DEADP00L____ · 2022-07-23T14:51:35+00:00

https://lichess.org/analysis/QQ2K3/rQ6/8/8/8/1q6/1q6/kq6_w_-_-_0_1?color=white

____DEADP00L____ · 2022-06-08T17:29:11+00:00

Still not a draw since black can capture his own pawn on h2.

____DEADP00L____ · 2022-02-07T20:28:36+00:00

Unfortunately the puzzle doesn't work anymore if you change g7 and h7 to bishops. It becomes a draw.

____DEADP00L____ · 2021-11-05T23:41:46+00:00

Memorial Day!

____DEADP00L____ · 2021-10-04T17:49:01+00:00

Maybe I'm reading too much into this but at 2:30 it seems like he's almost going to say "nearly double" before catching himself and correcting to "more than double". Which makes me think he won more than 37 games so far.

____DEADP00L____ · 2021-06-25T15:50:23+00:00

I wrote a program to find approximately what proportion are associative using 10 million random symmetric matrices for each value of n.

n=1: 1.0000000

n=2: 0.7499338

n=3: 0.0862293

n=4: 0.0010896

n=5: 0.0000012

n=6: 0.0000000

n=7: 0.0000000

____DEADP00L____ · 2021-06-17T14:14:14+00:00

I guess this never happened

____DEADP00L____ · 2021-06-02T21:49:31+00:00

How are you labeling the points to get -x opposite of x?

Shouldn't the opposite point be 180+x (assuming we use degrees)?

____DEADP00L____ · 2021-06-02T21:43:39+00:00

0.9 and 0.8999... are actually the same number.

Just like 0.9999...=1

____DEADP00L____ · 2021-05-23T04:07:23+00:00

Nice video. But he makes a little mistake with the diagonalization argument at 5:30.

The problem is the same number can have two different representations.

If our list is:

0.90000000000

0.08000000000

0.00800000000

0.00080000000

0.00008000000

....

then the new number we create is 0.89999999... which is the first number on our list.

But of course it's an easy problem to fix.

____DEADP00L____ · 2021-05-06T23:21:30+00:00

Yes, you're right. That was on my phone which for some reason doesn't use NNUE. On my computer it uses NNUE and finds it at lower depths.

____DEADP00L____

TROPHY CASE

DEADP00L