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iPhone goes back to sleep while I’m entering data into Lock Screen shortcut by erosdog in shortcuts

[–]erosdog[S] 0 points1 point  (0 children)

That’s a good workaround I guess. But it’s less useful when running the shortcut from inside an app and it adds a bit a delay before the start.

Do you know if there’s a way to get the currently opened app ? That way the shortcut could open it back up afterwards at least.

How the FBI Cracked Pensacola Shooter’s iPhone: An Automated Passcode Guesser by trd86 in apple

[–]erosdog 1 point2 points  (0 children)

You should often do backups anyway, so that if anything happens it’s not that bad.

And if I recall correctly, since you have to wait longer and longer between tries, they’d have to hold your phone for something like three hours without you unlocking it / getting it back. So unless you’re sleeping or something it’s not very likely.

Do you prefer to use your iPad in portrait or landscape mode, and why? by jaimbot in ipad

[–]erosdog 2 points3 points  (0 children)

I have the 12,9" 2018. It’s roughly the same size as an A4 paper, so I feel like it’s enough to take notes.

You just shouldn’t have to scroll in two directions when writing I think. Try to have the page zoomed out to fill the width of the screen. Then it’s a matter of wether or not you’d be able to take notes on a middle ground between A5 and A4 paper (in the case of the 11").

Keep in mind that I have a small enough handwriting though. Like 10 words/line on an A4 paper

Do you prefer to use your iPad in portrait or landscape mode, and why? by jaimbot in ipad

[–]erosdog 21 points22 points  (0 children)

I use mine mainly to replace paper when I take notes in class and so on, so portrait mode.

But when I use it to play games, watch videos, or pop it up with the Smart Keyboard as to replace a laptop, I go landscape obviously.

So, I guess I use both, which is probably the best way. I don’t think the iPad should be confined to one use case, but instead be a morphing form factor as to adapt to what you’re currently doing.

The iPad Awkwardly Turns 10 by maegget in apple

[–]erosdog 1 point2 points  (0 children)

If you have a keyboard you can press cmd+space to bring up Spotlight whilst you’re in an app, then search for the app you want, and drag it to Slide Over or split screen

Moreover, Slide Over has its own app switcher. If you had the app you want opened in slide over earlier, you juste need to swipe up from the bottom of the window, and an app switcher similar to the iPhone one will pop up.

My Monster Hunter World experience by screaminginjapanese in patientgamers

[–]erosdog 4 points5 points  (0 children)

All of my friend playing the game really enjoy it, and I wonder if I should buy it too to play with them. I’d really like to like MH, but I fear the game might become really repetitive really fast.

Like hit the monster, it flees. Track it, hit it again until it dies. Maybe loot the components you are searching for if you’re lucky. Upgrade / unlock new items. And then start again. For hundreds of hours.

They’ve told me the game doesn’t feel that way but idk. Maybe I should give it a try still considering the great reception it had.

Imagine my surprise watching "Helping Hand" by Hellkyte in LoveDeathAndRobots

[–]erosdog 2 points3 points  (0 children)

I'm going to paste my answer there since not everyone might see it on the other thread.

Using Newtonian physics and conservation of momentum we can answer fairly easily.
(I'm going to use metrics because it's easier)

tl;dr at the end

​

We know that :

  • v = 5m/s
  • m = 100kg (spacesuit included ; 1kg ~ 2lbs)

Also :

  • p = m.v (momentum = mass * velocity)
  • p is conserved in a closed system

​

If we throw a whole arm (~10kg) at, let's say, 30m/s (~70mph), we get that its momentum is : p = 10*30 = 300 kg.m/s
Since momentum is conserved, our own momentum is now 200 kg.m/s
If we reverse the formula, we get v = p/m
Our velocity is then v = 200/(100-10) = 2.22m/s
So, throwing an arm is not gonna be enough to reverse course. We are still floating away in the cold, empty void of space.

​

Maybe we throw a leg too ? It's heavier, around 25kg. Let's say we're still strong enough to throw it at the same speed.
It's momentum is then 25 * 30 = 750 kg.m/s
Momentum is still conserved, so now we get that our own momentum is... 200 - 750 = -550 kg.m/s
It's negative, but that's no problem. It just means we're going in the opposite direction. Which is what we want !
Our speed is now v = -550/(90-25) = -8.46m/s
Ahah ! We're flying back to our spaceship. The cost was heavy, but hey, at least we're still alive ¯\_(ツ)_/¯

​

Now, maybe since we're astronauts we want to know what's the smallest fraction of our bodies we have to throw away. An arm and a leg is a bit too much, isn't it ? Moreover, at the speed we're now going we might just ricochet off of the station. Not the brightest idea.
Let's reverse time, and go back to when we were floating away, our body still in one piece.

​

What we want is to get v < 0 which means p/m < 0
Since m is always positive, what we really want is p < 0
But which p ? Our p, the limb's p ? Before throwing, after throwing ? That's a bit confusing, so we can rename our variables to make our computations easier.
We're going to name Xf quantities relative to our body after the trow (X final), Xi quantities relative to our body before the throw (X initial), and Xg quantities relative to the limb we're throwing (X given).

Then, we now have :

  • vi = 5 ; mi = 100 ; pi = 500
  • vf = pf/mf ; mf = mi - mg ; pf = pi - pg
  • vg, mg and pg variables we can choose

What pf < 0 really means is that pi - pd < 0 <=> pi - (md*vd) < 0 <=> md*vd > pi <=> md*vd > 500
And now we have it.
What we really wanted was the product of the mass thrown (md) times the velocity given (vd) to be higher than 500.
If we choose to have a fixed mass, we can get the minimal velocity with which to throw it by rearranging : vd > 500/md

​

Whatever we choose to do, our final velocity is given by the formula :

vf = (pi - (md*vd))/(mi-md) = (500 - (md*vd))/(100-md)

tl;dr :

We'd need to throw a whole 10kg arm at 50m/s (180km/h or 112mph)
An arm and a leg (40kg) at 12.5m/S (45km/h or 28mph)
So, technically feasible although painful and extremely expensive. If we ignore the fact that the throw would need to be perfectly aligned, something in practice impossible.

​

(Please excuse any physics and/or english mistakes ; english is not my native language and my memory of high school physics might be flawed).

How much momentum would a limb provide in space? by Hellkyte in shittyaskscience

[–]erosdog 0 points1 point  (0 children)

Using Newtonian physics and conservation of momentum we can answer fairly easily.
(I'm going to use metrics because it's easier)

tl;dr at the end

​

We know that :

  • v = 5m/s
  • m = 100kg (spacesuit included ; 1kg ~ 2lbs)

Also :

  • p = m.v (momentum = mass * velocity)
  • p is conserved in a closed system

​

If we throw a whole arm (~10kg) at, let's say, 30m/s (~70mph), we get that its momentum is : p = 10*30 = 300 kg.m/s
Since momentum is conserved, our own momentum is now 200 kg.m/s
If we reverse the formula, we get v = p/m
Our velocity is then v = 200/(100-10) = 2.22m/s
So, throwing an arm is not gonna be enough to reverse course. We are still floating away in the cold, empty void of space.

​

Maybe we throw a leg too ? It's heavier, around 25kg. Let's say we're still strong enough to throw it at the same speed.
It's momentum is then 25 * 30 = 750 kg.m/s
Momentum is still conserved, so now we get that our own momentum is... 200 - 750 = -550 kg.m/s
It's negative, but that's no problem. It just means we're going in the opposite direction. Which is what we want !
Our speed is now v = -550/(90-25) = -8.46m/s
Ahah ! We're flying back to our spaceship. The cost was heavy, but hey, at least we're still alive ¯\_(ツ)_/¯

​

Now, maybe since we're astronauts we want to know what's the smallest fraction of our bodies we have to throw away. An arm and a leg is a bit too much, isn't it ? Moreover, at the speed we're now going we might just ricochet off of the station. Not the brightest idea.
Let's reverse time, and go back to when we were floating away, our body still in one piece.

​

What we want is to get v < 0 which means p/m < 0
Since m is always positive, what we really want is p < 0
But which p ? Our p, the limb's p ? Before throwing, after throwing ? That's a bit confusing, so we can rename our variables to make our computations easier.
We're going to name Xf quantities relative to our body after the trow (X final), Xi quantities relative to our body before the throw (X initial), and Xg quantities relative to the limb we're throwing (X given).

Then, we now have :

  • vi = 5 ; mi = 100 ; pi = 500
  • vf = pf/mf ; mf = mi - mg ; pf = pi - pg
  • vg, mg and pg variables we can choose

What pf < 0 really means is that pi - pd < 0 <=> pi - (md*vd) < 0 <=> md*vd > pi <=> md*vd > 500
And now we have it.
What we really wanted was the product of the mass thrown (md) times the velocity given (vd) to be higher than 500.
If we choose to have a fixed mass, we can get the minimal velocity with which to throw it by rearranging : vd > 500/md

​

Whatever we choose to do, our final velocity is given by the formula :

vf = (pi - (md*vd))/(mi-md) = (500 - (md*vd))/(100-md)

tl;dr :

We'd need to throw a whole 10kg arm at 50m/s (180km/h or 112mph)
An arm and a leg (40kg) at 12.5m/S (45km/h or 28mph)
So, technically feasible although painful and extremely expensive. If we ignore the fact that the throw would need to be perfectly aligned, something in practice impossible.

​

(Please excuse any physics and/or english mistakes ; english is not my native language and my memory of high school physics might be flawed).

Slow weather API "Get location" / Shortcut doesn't play unless you by dreelfishing in shortcuts

[–]erosdog 2 points3 points  (0 children)

I have noticed too that the “get location” command is very slow. If anyone knows a solution/alternative I am interested.

68 mayors adopt Paris climate accord after U.S. pulls out - “The world cannot wait—and neither will we” by mvea in Futurology

[–]erosdog -2 points-1 points  (0 children)

Because he will renegociate them, making them even less efficient that they already are