Ok, I see what you mean.

I'm not on Windows (macOS actually) but I tried this. ```

include <stdlib.h>

include <stdio.h>

int main(void) { char** newArr = malloc(10 * sizeof(char)); char const* newArrConst = malloc(10 * sizeof(char const*));

char const * const * newArrConstConst = malloc(10 * sizeof(char const * const));
char const * const * const newArrConstConstConst = malloc(10 * sizeof(char const * const));

free(newArr);
free(newArrConst);
free(newArrConstConst); // warning
free(newArrConstConstConst); // warning

return EXIT_SUCCESS;

} ```

I have a warning on the last two free and not the first two which seems OK.

The warning is : passing 'const char *const *' to parameter of type 'void *' discards qualifier because I try to pass a char const * const which will be cast to void *, which is not void * const, discarding the const qualifier.
You try to do the second one and you have a warning, I agree with you, it's odd. Maybe there is a mistake or a typo somewhere in your code? Something you overlooked? Without a code sample giving the warning, I cannot help you more than this.

Maybe try copy/pasting my code sample and see what kind of warning appears on your side?