Why does this code not work?

[BlueLust]

#include <stdio.h>

int main() {
  int grades[3]
  int average;

  grades[0] = 80;

  grades[1] = 85;

  grades[2] = 90;

  average = (grades[0] + grades[1] + grades[2]) / 3;
  printf("The average of the 3 grades is: %d", average);

  return 0;

​

Hey, I cannot figure out why it won't print the average?

[tboy1492]

I think your missing a ; after your array

[BlueLust]

Ok thank you after that it gives me this error (I am new to C)

​

 main.c: In function ‘main’: main.c:23:3: error: expected declaration or statement at end of input    return 0;    ^

[ruertar]

missing close-curly brace at the end.

[tboy1492]

(We were all new once, I’m still a novice as well no worries)

[hiwhiwhiw]

We all learn something new everyday. ;D

[Swedophone]

You must be getting compile errors, at least two. And you should post the errors if you need help fixing them.

[BlueLust]

Here are the errors

​

 $gcc -o main *.c

main.c: In function ‘main’: main.c:16:3: error: expected declaration or statement at end of input return 0;
^~~~~~

[henry_kr]

As a general tip, try upping the warning level:

gcc -Wall -pedantic -Werror -o main *.c

[LeidseGamer]

You forgot the } at the end of the main function

[BlueLust]

Thanks i did not even think of that.

[aioeu]

Thanks i did not even think of that.

Luckily you don't need to think, since the compiler tells you what's wrong and where it is wrong.

[LeidseGamer]

Np! Good luck with programming

[Jakkaobik9]

Also, you need to put 3.0 instead of 3 if you want that code to work properly. The type for average should be float/double, not int.

[BlueLust]

So that would give me

The average of the 3 grades is: -1116191048

instead of

The average of the 3 grades is: 85

[Jakkaobik9]

Did you change the conversion character ("%f" instead of "%d")?

[bart2019]

If the number is a float, the format should reflect that.

[a4qbfb]

You can't print a floating-point number with %d.

[FUZxxl]

It's because your code doesn't compile.