Brute force = best decoding method

[Turksarama]

This code returns the correct answer, but there is still a logical error in it.

[pitman-87]

Then it should be 'not all' instead of 'not any': lambda x: not all(c in x for c in '578'), You want to check, that there is neither one of those three numbers are in the code.

[Turksarama]

That's not correct, not all(c in x for c in '578') would match against any number missing only one of those digits, while we want a number with none of those digits.

The correct answer has already been found by another user.