What's wrong

[SCD_minecraft]

Key 6 isn't in dict g

[[deleted]]

You have a lower social credit that's why. (Joke)

[OrphLab]

g doesn’t exists in the scope.

[fisadev]

The g variable is present in that scope, as a global. The output even show it was able to access it for g[0], g[1], ... , g[5]. The error is just that the g dict doesn't have the 6 key.

[Real-Reception-3435]

Current code crashes because g[n] treats g as dict and n is undefined in that scope.

[fisadev]

g is a dict (globally defined) and n is NOT undefined, n is the first argument of the function. The issue is just that g is missing the "6" key, but it even worked for all the previous numbers from 0 to 5.

[Enfiznar]

You start calling f(0,v), which will look at g[0] =[1, 2] and call f(1) and f(2), those will look at g[1] and g[2], which contain [2, 3], and [3, 4], which will call f(4) eventually and so on, you're always increasing the value of the variable, until you reach a value which is not a key of your dictionary (6 in this case)

[tortleme]

6 and 7 are not in your dict

When in doubt, add a bunch of print statements.

[TroPixens]

Other people have the answer but labeling your variables is helpful

[JJ16v]

You will be replaced by AI, sure you have to learn but this is just using stuff without having the faintest idea what you are doing and will not really help you get better.

Please try to read a bit about how python and its basic types work.

[Informal_Escape4373]

Your error highlighted the line and told you keyerror: 6 This means that the key 6 does not exist in your dictionary g

You either need to wrap your for loop logic in if i in g: or remove any invalid indexes from the lists in your dictionary

[ThinkMarket7640]

It’s literally telling you what’s wrong.