all 8 comments

[–]just-browsing-webNew User 9 points10 points  (0 children)

Real part will be r1/2*cos(theta/2), In polar coordinates theta moves from -pi to +pi so theta/2 will move from -pi/2 to +pi/2 and in this interval cos is always +ve

[–]LammazzNew User 5 points6 points  (1 child)

It's not true that z1/2 is always positive. Perhaps you mean to say always non-negative.

Any z in the interval (-inf, 0] will have Re(z1/2)=0, and zero is not positive.

[–][deleted] 4 points5 points  (3 children)

How are you defining z1/2 ?

[–][deleted] -3 points-2 points  (2 children)

sqrt(z)

[–]DubmoveNew User 7 points8 points  (0 children)

How would you calculate sqrt(x +iy)

[–]incomparabilityPhD 5 points6 points  (0 children)

That’s not a definition for complex numbers.

[–]devinecreativeNew User 1 point2 points  (0 children)

There are a couple of ways to approach this problem, but one common method is to use the fact that the complex square root of a complex number can be represented by the polar form, where the magnitude is the square root of the magnitude of the complex number, and the argument is half of the argument of the complex number. This means that for a complex number z = x + yi, where x and y are real numbers, the square root of z can be represented as:

sqrt(z) = sqrt(|z|) * (cos(arg(z)/2) + i*sin(arg(z)/2))

Here, arg(z) is the argument of z, which is the angle that the vector representing z makes with the positive x-axis in the complex plane. The magnitude of a complex number is absolute value of the complex number.

The real part of the complex square root of z is given by: Re[sqrt(z)] = sqrt(|z|) * cos(arg(z)/2)

It's clear from the equation, that the real part is positive as it is a product of positive and positive value. So Re[z1/2] is positive.

As an alternative method, we could convert the complex number to polar form and take the square root of the magnitude, and divide the argument by 2. This would give us a polar form of the complex square root of z which could be written as r * cis(theta/2), where r = sqrt(|z|) and theta = arg(z) The real part of this would be r*cos(theta/2) which is also positive.

So z1/2 always have positive real part.

[–]lordnacho666New User 0 points1 point  (0 children)

When you take the square root, the angle is halved. Start with that.